A lamp with a thick filament will draw more current.
What restricts the current flow in the filament is the resistance of the filament which increases as the temperature of the filament increases. A thin filament requires less energy to get heated up that a thick one so less current to achieve threshold resistance. Also a thick filament provides a broader path for current so there is less resistance per increase in degree centigrade. For these two (closely related but distinct) reasons it will require more current for the filament to get heated up to threshold resistance.
Electric lamps having incandescent filaments.
An incandescent lamp is a type of electric light bulb that produces illumination by heating a filament, typically made of tungsten, until it glows. This process involves passing an electric current through the filament, which emits light as it becomes hot. Incandescent lamps are known for their warm light quality and are often used in household lighting, though they are less energy-efficient compared to newer technologies like LED or CFL bulbs. Despite their declining popularity due to energy regulations, they remain valued for their aesthetic qualities in certain applications.
Argon is used in fluorescent lighting as an inert gas that helps create a low-pressure environment within the lamp. When an electric current passes through the argon gas, it produces a faint blue light. This blue light then excites a phosphor coating on the inside of the bulb, which emits visible light. Additionally, argon helps to prevent the oxidation of the filament, enhancing the lamp's longevity and performance.
I was also searching for the same but according to me the lamps with higher wattage should glow brighter. We know that, P=VI In series connection current is same through all the lamps but voltage across each lamp depends on the wattage of the bulb. So the bulb with higher wattage will draw more voltage and glow brighter.AnswerUnfortunately, the previous answer is incorrect, although it seems* to be the logical answer! The higher-wattage lamp has a lower resistance than the lower-wattage lamp. So, when they are connected in series, the larger voltage drop (IR)will appear across the lower-wattage lamp. As power is proportional to the square of the voltage, it is the lower-wattage lamp that will be the brighter.[*Many people have the mistaken belief that a higher-wattage lamp has a higher resistance than a lower-wattage lamp. That's the wrong way around!]
A starter in a fluorescent tube is a small device that helps initiate the lighting process by preheating the electrodes inside the tube. When the fluorescent lamp is turned on, the starter quickly closes the circuit, allowing current to flow through the gas and ignite the lamp. Once the lamp is lit, the starter disengages from the circuit, allowing the lamp to operate normally. Starters are typically used in older fluorescent lighting systems, while newer designs often rely on electronic ballasts that eliminate the need for a starter.
A lamp with a thick filament will draw more current. What restricts the current flow in the filament is the resistance of the filament which increases as the temperature of the filament increases. A thin filament requires less energy to get heated up that a thick one so less current to achieve threshold resistance. Also a thick filament provides a broader path for current so there is less resistance per increase in degree centigrade. For these two (closely related but distinct) reasons it will require more current for the filament to get heated up to threshold resistance.
The lamp with the thicker filament has a lower resistance compared to the one with the thin filament. According to Ohm's law, lower resistance allows more current to flow through the thicker filament when connected in parallel to the same voltage source. This increased current results in a higher power output (P = I²R), causing the lamp with the thicker filament to burn more brightly.
The filament is fine so that its electrical resistance can be quite high. It is also long, for the same reason. Usually it is coiled up to fit the length in the lamp. The heating effect of electric current is proportional to the current squared, time the resistance (I*I*R). Most of the effect is due to the current. The current through the filament must be limited to stop it melting. Adding resistance will do that. Taking resistance away increases heating. So, a low energy lamp has a very thin filament and a high energy lamp will have a thicker filament.
I had to answer this and found out that............ The line on the graph that represents the filament lamp is curved because the resistance of it increases with supplied voltage Hope this is alright for you :) x
Since power is volts time amps, the current in a 60W lamp connected to 120V is 0.5A. Since a lamp is a resistive load, there is no need to consider power factor and phase angle, so that simplifies the explanation. ======================== Assuming this is an incandescent or halogen lamp (using a filament to make the light) there is a trick here: the resistance of a lamp filament varies with temperature and does not follow Ohm's law. The resistance will be much lower, thus the current will be much higher when the filament is cold, when the lamp is first connected. As the filament heats up, the resistance increases until it gets to a steady operating point of 0.5A. For a halogen lamp, the operating temperature is about 2800-3400K, so the R at room temperature is about 16 times lower than when hot... so when connected, the current is about 8A but drops rapidly. The current could be even higher if the lamp is in a cold environment. Non-halogen lamps operate at a lower temperature and would have a lower initial current--about 5A. And this all assumes the lamp is rated for 120V. If it is a 12V/60W lamp, the filament will probably break and create an arc, which may draw a very large current.
A filament lamp produces light by converting electrical energy into heat and then light. It acts as a resistive load in the circuit, meaning it resists the flow of current and causes the filament to glow and produce light.
Your standard light bulb where a filament is heated by a current passing through it. The heated filament then gives off light.
Well, honey, the filament lamp doesn't give a hoot about Ohm's Law because its resistance changes with temperature. As the current increases, the temperature of the filament rises, causing the resistance to also increase. It's like trying to control a wild horse - good luck getting it to follow any law!
The answer is no. However, it will run out of electricity if you put a lot of energy into the light bulb when you switch it on. Thank you for asking young fellow person who is unknown to me. -Your fellow friend
because there is a correlation between resistance and voltage and current. The equation resistance = voltage divided by current shows that the higher the voltage, the bigger the resistance,, and the bigger the resistance the hotter the filament lamp will get because of the electrons bumping into each other which means there is a loss of energy and that energy is being transferred to the filament making the actual filament bulb hot since there is more thermal energy wasted at the end.
A lamp with a higher wattage rating will consume more current. The higher the wattage, the more electricity the lamp will draw from the power source.
The relationship between the voltage and resistance in a filament lamp is non-linear. As the voltage increases, the resistance in the filament of the lamp also increases due to the heating effect. This increase in resistance causes the current to increase at a slower rate than expected, leading to a non-linear slope in the voltage-resistance graph.