I was also searching for the same but according to me the lamps with higher wattage should glow brighter. We know that, P=VI In series connection current is same through all the lamps but voltage across each lamp depends on the wattage of the bulb. So the bulb with higher wattage will draw more voltage and glow brighter.
Unfortunately, the previous answer is incorrect, although it seems* to be the logical answer! The higher-wattage lamp has a lower resistance than the lower-wattage lamp. So, when they are connected in series, the larger voltage drop (IR)will appear across the lower-wattage lamp. As power is proportional to the square of the voltage, it is the lower-wattage lamp that will be the brighter.
[*Many people have the mistaken belief that a higher-wattage lamp has a higher resistance than a lower-wattage lamp. That's the wrong way around!]
Because the filament of a 40-W lamp has a higher resistance than that of a 60-W lamp and, therefore, will experience a greater voltage drop -the lamp with the voltage drop closer to its rated voltage (in this case, the 40-W lamp) will be the brighter.
The manufacturers of light bulbs want to give their customers light. This requires the use of energy (Watts) which cost money for their use. Manufacturers design their light sources so that users get as much light as possible from the bulb for a given wattage while maintaining a reasonable lifetime (otherwise we would just get flash bulbs).
it is because watts is the same thing as joules per second. That is how much energy can be done in a second (the unit of time). A 60 watt bulb releases 60J energy in one second where as a 25 watt bulb releases 25J in one second Hope this helps😄
The conservation of energy means energy isn't created or destroyed. So the energy you put in is equal to the energy you get out (but it may be transformed into different types of energy).
Electrical energy (or power) is measured in Watts, where 1 watt second = 1 joule. A watt is equal to the voltage applied times the current (ignoring any phase shift due to inductance and capacitance of the circuit, a valid assumption for your case).
If you measure the voltage and current under your two situations (series and parallel), you will notice that the current changes, but the voltage will remain constant. Specifically, the current will increase (by a factor of four if the light bulbs are the same) in the parallel circuit compared to the series circuit.
Conservation of energy is not violated specifically because more energy is pumped into the parallel circuit, which then produces more light and heat; the amount of light and heat produced will be 4 times more in the parallel circuit compared to the series circuit.
The reason 4 times: Take the resistance of the light bulb to be R, then the resistance of two light bulbs in series is R+R = 2R; the resistance of two light bulbs in parallel is:
R*R/(R+R) = R/2. Using Ohm's law, I = V/R, it is evident that 4 times more current (and thus four times more power) will be flowing to the parallel circuit.
The filaments in the bulb are larger and draw more electricity. The bulbs also get hotter if you will notice.
The filament in a higher wattage bulb is actually smaller than a lower wattage bulb. The smaller filament has less resistance which allows for more current to flow. More current, more heat, more light.
A lamp will only operate at its rated power if it is subject to its rated voltage (both values are printed on a lamp). It follows, then, that the lower the voltage you apply to a lamp the dimmer it will become.
When lamps are connected in series, a voltage drop will appear across each lamp (Kirchhoff's Voltage Law), and this voltage drop is the product of the current flowing through it and the resistance of its filament. As more powerful lamps have a lower resistance than less powerful lamps, the voltage drop across a more powerful lamp will be lower than the voltage drop across a less powerful lamp. So, when different lamps are connected in series, the less powerful lamps will have greater voltage drops across them, and will operate brighter than the more powerful lamps. ALL the lamps will illuminate at about the same time (depending how long it takes for their filaments to heat up) because the same current flows through them at the same time.
the 40 watt bulb will glow brighter in series because it will consume less power.
A: A BULB in parallel has available all the power that the source can supply. In series the power divide according to each bulb resistance.
You will have 24 volts DC.
"series" ... high voltage
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The battery connected to the bulb has the potential chemical energy in it when it is connected by means of wire to the bulb the chemical energy in the battery is converted to the electrical energy which flows through the wire to the bulb glows the bulb which is a form of light energy after some time the bulb starts emitting heat which is heat energy.
lower wattage bulb
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.Another AnswerWhen two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
It will if the batteries are connected in series. If they are connected in parallel, the lamp will burn longer, but not brighter.
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.
If you put two incandescent bulbs of the same wattage in series, they will both light with the same intensity. If one is lower wattage than the other, the lower wattage bulb will light brighter than the oter one. If you put two 115 volt bulbs of the same wattage in series across 230 volts, both will light equally, but if you use dissimilar wattages, the smaller one will burn out.
Parallel connections will draw more current than equivalent lights connected in series, so the parallel configuration will be brighter.
No, the highest wattage bulb will have the lowest resistance.
Two bulbs connected in parallel are brighter than two connected in series. The resistance of the circuit is lower, electrons can flow more easily.
Resistance wise, the rated wattages are immaterial. When calculating the amount of power the two of them would be able to dissipate, (or the maximum current) you would have to use V=IR and P=VI to work out which resistor would run into it's wattage rating first.
Brighter in parallel. In series the voltage is divided between the two bulbs, thus the current will only be half so that the power of each bulb will only be one quarter (of 5 watts) in the series set-up.
The 40-W lamp will be the brighter, because it has a greater resistance that the 60-W lamp and, therefore, will experience a greater voltage drop across its terminals. The closer the voltage drop is to the lamp's rated voltage, the brighter it will be.