False a force at any angle to the direction of motion can not perform work. Power is the rate at which a force is applied.
A force acting on the ball, at an angle to its line of motion, will cause its direction of motion to change.
If the force is perpendicular (at 90 degrees) to the direction of motion, that force does no work.
Work is "defined " as force in the direction of displacement or fdcos(angle), so if the angle is zero the work is maximum. A better definition is to realize that work is the product of force times displacement w=fd= -fdcos(a) + fdsin(A). Here we see that there is real work -fdcos(A)and vector work (commonly called torque) fdsin(A). Notice also that work is negative at angle zero, force and displacement in the same direction and work is positive when the direction is opposite. The differnece in sign is exergy or energy.
certainly. The force vector can be resolved into one component parallel to the motion of the object under force and another component perpendicular to the motion. The parallel component does the work; the perpendicular component does no work
When force is opposite to the direction of motion, no work is done. The object to which the force is applied must move in the direction of the force in order for work to be done.
A force acting on the ball, at an angle to its line of motion, will cause its direction of motion to change.
If the force is perpendicular (at 90 degrees) to the direction of motion, that force does no work.
If a force is acting at an angle to the direction of motion then it is usually helpful to study components of the force along the line of motion and at right angles to it. For a force of magnitude f, acting at an angle x with the line of motion, the component along that line is f*cos(x).
Work is "defined " as force in the direction of displacement or fdcos(angle), so if the angle is zero the work is maximum. A better definition is to realize that work is the product of force times displacement w=fd= -fdcos(a) + fdsin(A). Here we see that there is real work -fdcos(A)and vector work (commonly called torque) fdsin(A). Notice also that work is negative at angle zero, force and displacement in the same direction and work is positive when the direction is opposite. The differnece in sign is exergy or energy.
Work is zero when the force is perpendicular to the direction of motion, as it is, for example, in a circular gravitational orbit.
If the angle between force and displacement is between 90 to 270 degree because value of cosine trignometric function is negative within these limits.work=fdcos(angle)
certainly. The force vector can be resolved into one component parallel to the motion of the object under force and another component perpendicular to the motion. The parallel component does the work; the perpendicular component does no work
You mean a force I guess. A force acting on an object will make it accelerate or decelerate, and if it is acting at an angle to the existing line of motion will make it change direction.
The direction of the force of friction is opposite of the direction of the motion.
The direction of the force of friction is such that it opposes the direction of motion that an object would move if there were no frictional force acting on the object.
When force is opposite to the direction of motion, no work is done. The object to which the force is applied must move in the direction of the force in order for work to be done.
work