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Work is the force times distance, so the answer is 2,850,000 joules.
2,088 J
The total work done on the object, from beginning to end of that scenario, is equal tothe change in the object's potential energy from beginning to end, which is zero.
The total force is the vector sum of the individual forces.
A force of 10 newtons acting through a distance of 10 meters does 100 joules of work. Power is defined as the rate at which that work is done. So the power during the push is (100) divided by (the number of seconds the push lasts). Doing the job in less time indicates more power, just as you'd expect. But the total energy delivered is still 100 joules, regardless of how slowly or quickly it's delivered.
W = Fd; d = W/F = 150 J/100 N = 1.5 m
W = Fd; d = W/F = 150 J/100 N = 1.5 m
Work is the force times distance, so the answer is 2,850,000 joules.
Work is the force times distance, so the answer is 2,850,000 joules.
It's necessary to remove 540 calories from a gram of water in order to freeze it. That's about 2260 joules. The amount of energy used by a freezer to do this depends on the efficiency of the freezer.
yes kilojoues convert down to joules which is the amount of energy in the body total joules= total energy
Watts = joules / secondYou need to divide the total annual energy consumption by the number of seconds in a year (which is about 31.5 million).
You can't convert from Joules to Watts because Joules is a measure of total energy, and Watts measure energy per second.
3,876,831,120,000 :P
700 joules
Joules
2,088 J