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It's necessary to remove 540 calories from a gram of water in order to freeze it. That's about 2260 joules. The amount of energy used by a freezer to do this depends on the efficiency of the freezer.

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When 1 gram of liquid water at 0 degrees celsius freezes to form ice how many total joules of heat are lost by the water?

a change from liquid to solid or solid to liquid will require the use of the formula of Heat of Fusion , q=mHf where m is the mass and Hf = 334J/g, this is standard so you wont have to look for how it came about.In this case the m=5.00g so: q = m Hf q=(5.00g)(334 J/g) , you notice the grams will cancel out. q = 1670 J.


What is the total temperature change between 1000 m and 4000 m in depth?

The average temperature gradient in the Earth's crust is approximately 25-30 degrees Celsius per kilometer of depth. Therefore, the total temperature change between 1000 m and 4000 m in depth would be around 75-120 degrees Celsius.


What is the total temperature change between 3km and 7 km above earths surface?

The temperature decreases by about 6.5 degrees Celsius per kilometer in the troposphere, so the total temperature change between 3 km and 7 km above the Earth's surface would be approximately 26 degrees Celsius.


How many joules are necessary to raise the temperature of 53.5 grams of water from 16.5 degrees celsius to 70.1 degrees celsius?

Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.


How much heat does 32.0 g of water absorb when it is heated from 25.0 Celsius to 80.0 Celsius in calories?

Water has a specific heat of 1 calorie per gram per degree. This means that in order to raise 28.4 grams of water by 1 degree Celsius, it takes 28.4 calories. At an increase of 44.6 degrees Celsius, this equates to 1,266.64 calories of heat.

Related Questions

When 1 gram of liquid water at 0 celsius freezes to form ice how many total souls of heat are lost by the water?

When 1 gram of liquid water at 0 degrees Celsius freezes to form ice, it releases 334 Joules of heat.


What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?

Approx 4974 Joules.


How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?

To bring the ice block to 0 degrees Celsius, you would need 150,000 Joules (Q = mcΔT). To melt the ice at 0 degrees Celsius, you would need 3,375,000 Joules (Q = mLf). Heating the water from 0 to 100 degrees Celsius would require 1,500,000 Joules (Q = mcΔT). Turning the water to steam at 100 degrees Celsius would need 10,500,000 Joules (Q = mLv). Finally, heating the steam to 120 degrees Celsius would require 600,000 Joules (Q = mcΔT). In total, you would need 15,125,000 Joules of heat energy.


How much joules does it take to heat water to 100 degrees?

To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.


What is the temperatures when liquids freeze?

The temperature varies from one liquid to another. Every element has a different freezing point and boiling point. You can calculate both for a molecule by using a formula that takes into consideration the different elements that make up the molecule in comparision to percentage that element is of the total mass of the molecule


What is the total of degrees in any circle?

1387 degrees celsius.


You have 100 liters of H2O at 25 degrees Celsius and you add 50 liters of H2O to it. What temp. does the 50 liters of H2O need to be for the total amount of H2O to equal 35 degrees Celsius?

100 degrees Celsius


When 1 gram of liquid water at 0 degrees celsius freezes to form ice how many total joules of heat are lost by the water?

a change from liquid to solid or solid to liquid will require the use of the formula of Heat of Fusion , q=mHf where m is the mass and Hf = 334J/g, this is standard so you wont have to look for how it came about.In this case the m=5.00g so: q = m Hf q=(5.00g)(334 J/g) , you notice the grams will cancel out. q = 1670 J.


How much heat energy is needed to convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius?

539 calories per gram for heat of vaporization plus 1 cal/gram/degree C 100 degrees C - 80 degrees C = 20 degrees C (539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal


How many calories are needed to convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius?

To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.


What is the total temperature change between 1000 m and 4000 m in depth?

The average temperature gradient in the Earth's crust is approximately 25-30 degrees Celsius per kilometer of depth. Therefore, the total temperature change between 1000 m and 4000 m in depth would be around 75-120 degrees Celsius.


4 kg of ice at 0 degrees Celsius is converted to steam at 100 degrees Celsius How much heat is needed?

To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.