Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.
q(Joules) = mass * specific heat * change in temperature
q = 53.5 grams H2O * 4.180 J/gC * (70.1 C - 16.5 C)
= 11987 Joules
Only 3 significant figures should be used given the numbers in your question. The answer would be correctly written as: 1.20 kJ
q = m x C x (Tf - Ti)
q = amount of heat energy gained or lost by substance m = mass of sample in grams = 2.83kg = 2830g C = heat capacity (J/ g•oC) = 4.18J/ g•oC
Tf = final temperature = 46 oC
Ti = initial temperature = 38 oC
(Tf - Ti) = 46 oC - 38 oC = 8 oC
q = 2830g x 4.18J/ g•oC x 8 oC = 9.46 x 104 J
The number of joules to raise one gram of water by one degree Celsius is 4.2 Joules. The total number of joules needed then is 95,088 joules.
It takes 4.2 joules per gram of water to raise the temperature by one degree Celsius. The total number of joules is then 190.176 kilojoules.
46 calories (or 192,464 joules) for each Celsius degree.
q(Joules) = mass * specific heat * change in temperature
q = (20 grams H2O)(4.180 J/gC)(40o C - 30o C)
= 836 Joules needed
===============
0.0796636 J
Temperature is measured in celcius.Heat is measured in joules.
Heat is measured in unit of what...
Go back and find out how much water there was, and what temperature it started out. Then come back with that information and we can answer your question.
q = [ 0.803 J/( g degrees Celsius)] ( 2 multiplied by '10 to the power of 6' grams) ( 19 degree Celsius) q = 3.1 multiplied by '10 to the power of 7' Joules
q( Joules) = mass grams * specific heat * change in temperature 90 kj = 90000 Joules 2 kg = 2000 grams 90000 Joules = (2000 g)( SP )(200 C - 80 C) 90000 = 240000(SP) 0.375 J/gC ( The actual specific heat of copper is 0.385 J/gC, so close enough for the problem type )
15.37684 joules
The answer is 53,683 kJ.
8.200 J
Temperature is measured in celcius.Heat is measured in joules.
Approx 4974 Joules.
15480.80
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
10 degrees Celsius
It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.
3.8 x 10^5 Joules
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams