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q = [ 0.803 J/( g degrees Celsius)] ( 2 multiplied by '10 to the power of 6' grams) ( 19 degree Celsius)

q = 3.1 multiplied by '10 to the power of 7' Joules

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Q: How many joules of heat are lost by 3580 kg of granite as its cools from 41.2 degreees Celsius to -12.9 degrees Celsius?
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