c(*) x mass x delta (change in temp)=joules
4186x1.92(**)x80o =joules
642969.6 joules
15.37684 joules
15480.80
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
I assume you mean 30o Celsius. Use this formula.q(joules) = mass * specific heat * change in temperatureq = (15 grams water)(4.180 J/gC)(40o C - 30o C)= 627 joules==========( perhaps 630 joules to be in significant figures territory )
21 grams through 71 degrees is 21x71 calories.
15.37684 joules
3.8 x 10^5 Joules
Can you help
8.200 J
Heat is measured in unit of what...
Approx 4974 Joules.
Temperature is measured in celcius.Heat is measured in joules.
q = [ 0.803 J/( g degrees Celsius)] ( 2 multiplied by '10 to the power of 6' grams) ( 19 degree Celsius) q = 3.1 multiplied by '10 to the power of 7' Joules
The answer is 53,683 kJ.
15480.80
There is not enough information in this problem to answer the question. You must know the mass of the iron to find the amount of joules used to heat the iron.
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.