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If the satellite appears to remain motionless over one spot on the earth, then I don't
need to know the radius or anything else about orbital mechanics to calculate its period.
It had better be equal to the earth's rotation period of 23hours 56minutes and about 4 seconds.

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14y ago
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14y ago

We'll assume that the number given for the orbital radius is in meters.

The circumference of the orbit is [ pi D ] = [ 2 pi R ] = [ 8.46 x 107 pi ] = 2.6578 x 108 meters (rounded).

The orbital period = earth's rotation period = 23hours 56minutes 4seconds = 86,164 seconds (rounded)

Speed in orbit = (distance) / (time) = 2.6578 x 108 / 86,164 = 3,084.6 meters per second (rounded)

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Q: A geosynchronous satellite appears to remain over one spot on the earth its orbital radius is 4.23 x 107 calculate its speed in orbit?
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