no not always they can transmit a dominate trait also
A male carrying a recessive allele on the X chromosome will exhibit the recessive trait. This is because the Y chromosome generally does not have matching genes for the X chromosome, unlike the other 22 pairs if chromosomes in the nucleus.
A heterozygous recessive male has one dominant allele and one recessive allele for a trait, like curled ears. If the curled ear trait is recessive, it will only be expressed in offspring if they inherit two recessive alleles (one from each parent). Therefore, if the mother is also heterozygous or homozygous recessive, there is a chance for curled-eared offspring, but if she is homozygous dominant, the male cannot produce curled-eared offspring. The specific chances depend on the genotype of the female parent.
There are 2 X-linked recessive inheritance where Only Male or Men are the only people who inherits these kind of trait.
The gene relationship most likely to result in a portion of offspring that are all recessive males would involve X-linked recessive inheritance. In this scenario, if a male inherits a recessive allele on the X chromosome from his mother (who may be a carrier or affected), and the father contributes a Y chromosome, the male offspring will express the recessive trait. If the mother carries two recessive alleles on both X chromosomes, all male offspring will inherit the recessive trait, resulting in a population of recessive males.
In genetic diagrams, a male carrier of a recessive trait is typically represented by a square with a half-shaded or partially shaded symbol. This shading indicates that he carries one copy of the recessive allele but does not express the trait. If using a pedigree chart, a carrier male may also be marked with a dot inside the square to signify his carrier status.
k so. i think you meant marries a woman? lol k so its recessive carried on the X chromosome. Her father genetic make up is X^b Y. marries a woman who has the trait is X^H X^h (since its recessive and dominant overthrows recessive and she has the trait h). so use a punnet square. you should get.. two girls. one is afflicted, the other one carries the trait. two boys: a normal son, and an afflicted son. Hope this helps!
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
A male only needs one copy of a sex-linked recessive allele to exhibit the trait because males have only one X chromosome. If the allele is present on the X chromosome, it will be expressed in males.
a male with one recessive allele
When a male plant that is true breeding for the recessive trait of wrinkled seeds (genotype: rr) is crossed with a female plant that is true breeding for the dominant trait of round seeds (genotype: RR), all the offspring will inherit one allele from each parent, resulting in the genotype Rr. Since the round seed trait is dominant, all offspring will display the round seed phenotype.
A heterozygous male parent has two different alleles for a trait. During gamete formation, each sperm cell will carry one of the two alleles, either the dominant or recessive allele. This means that half of the sperm cells will carry one allele and the other half will carry the other allele.
An X-linked recessive trait is coded for by a gene on the X-chromosome and is not dominant (is canceled out by the presence of a different allele). Example of X-linked recessive traits are; Haemophilia A & B and Duchenne muscular dystrophy.