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Assume the mixture is homogeneous CuOx. That makes the molecular weight 64 + (x(16)) You know that the oxygen is 12% of the mass, so work from that to find x. That gives the contribution of oxygen to the total molecular weight, which comes to less than 16, so you have not posted the question correctly or it is wrong for some other reason. In CuO, the copper content is 80%, in CuO2 it is 67%, there is no combination of the two oxides that would give 88% copper.

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Q: A mixtue of CuO and Cu2O contains 88 percent Cu What is the percentage composition of mixture?
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