Assume the mixture is homogeneous CuOx. That makes the molecular weight 64 + (x(16)) You know that the oxygen is 12% of the mass, so work from that to find x. That gives the contribution of oxygen to the total molecular weight, which comes to less than 16, so you have not posted the question correctly or it is wrong for some other reason. In CuO, the copper content is 80%, in CuO2 it is 67%, there is no combination of the two oxides that would give 88% copper.
note: NOT percent composition.
Percent composition is usually expressed as a percent by mass, but in the case of gases and vapors, it is often expressed as a percent by volume.
This is the composition of the air.
The composition of Be in BeO = 9 / 25 = 0.36 or 36%
hydrogen and helium
Percent composition can be used to calculate the percentage of an element/compound in a mixture. From the percent composition, you can also find the empirical formula. And from the empirical formula you can find the actual molecular weight.
note: NOT percent composition.
Yes, you can.
You can use percent composition to see how much much flour contributes to the mass of an overall cake. You can see how much kool aid powder is in a given amount of kool aid drink, in percentage. Percentage composition can be used for virtually anything that has a mixture of things. So you don't always have to think percentage composition refers to chemical compounds, such as H2O or KMnO4.
the percentage composition of aluminum sulfate is 342
This is the percent chemical composition.
The percentage of oxygen is 28,91 %.
A way of describing the concentration of solute in a compound or mixture is called Mass percentage or percent composition by mass. It can be calculated by dividing the mass of a component by the total mass of the mixture, then multiply the answer by 100%.
Mercury's internal composition is made up of 70 percent metals and 30 percent silicate. The core is a hot, liquid iron-nickel mixture.
40%
Mole percent, or molar percent of a substance is the ratio of the moles of a substance in a mixture to the moles of the mixture. It represents the number of moles of a substance in a mixture as a percentage of the the total number of moles in the mixture. Mole % = (mol substance in a mixture) / (mol mixture) * 100
The original mixture contains 41.4 ounces of glycol. for this to be 30 percent of the mixture, the total mixture must be 138 ounces, so 46 ounces of water must be added.