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Mole percent, or molar percent of a substance is the ratio of the moles of a substance in a mixture to the moles of the mixture. It represents the number of moles of a substance in a mixture as a percentage of the the total number of moles in the mixture.

Mole % = (mol substance in a mixture) / (mol mixture) * 100

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Is mole percent equal to atomic percent?

No.


1.61 mole percent to PPM?

1.61 mole percent is equivalent to 16,100 parts per million (PPM). This conversion is based on the fact that 1 mole percent is equal to 10,000 parts per million.


Is mole percent equal to weight percent?

No, the two concepts are quite unrelated.


Is mole percent of a gas is equal to its volume percent?

No, mole percent and volume percent are not necessarily equal for a gas. Mole percent is the ratio of the moles of a gas to the total moles of all gases in a mixture, while volume percent is the ratio of the volume of a gas to the total volume of all gases in a mixture. The two can be equal only if the gases have the same molar volume at the given conditions.


What is weight of 2 mole percent of molecular iodine?

.005078 g is the weight of 2 mole percent molecular iodine.


How do you convert mole fraction to volume fraction of liquid?

You need the balanced symbol equation for the reaction. The numbers in front of the formulae show the mole ratios. For example, in the thermal decomposition of calcium carbonate: CaCO3 --> CaO + CO2 The equation is balanced. The mole ratio between CaCO3 and CO2 is 1:1 because there is 1 mole of CaCO3 for every mole of CO2


What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?

To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.


What is the percent sulfate in CuSO4.5H2O?

If i understand the question as a percent of sulfate in a compound of Cu(ii)5+(So4)5. If i can remember the formula take the total molar mass of Cu5 as 317.75g/mole and of (So4)5 480.35g/mole add them together, 317.75g/mole + 480.35g/mole this becomes your denominator. Take the mass of sulfate and place in the numerator and the outcome is the multiplied by 100. (So4)5 480.35g/mole --------------------------------------------------------- = .60187 x 100 = 60.187% Cu5 (317.75g/mole) + (So4)5 (480.35 g/mole) But this will not answer the percent if it is an amount of compound in an amount H2o you would need to separate the compound from the water then take there weights and divide them by there weights prior to separation. The above answer is theoretical based on percent of sulfate in a molecule of Cu5(So4)5.


The percent yield of 1 mole NaHCO3 was used and 22 g carbon dioxide was isolated is?

50 mol%, because 22 g CO2 = 0.5 mole


What formula do you use to find a solution stregth?

Your question doesn't have a single answer. In Chemistry solution strength is usually calculated in moles pe liter of mole per kilogram or as a mole fraction ( moles per mole) but can also be mass per liter, mass per mass, volume per volume, percent by mass, or percent by volume.


What is the empirical formula of a compound that is 40 percent sulfur and 60 percent oxygen by weight?

We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula


Mass percent of sol of benzene in toulene when mole fraction of benzene is 0.40?

To calculate the mass percent of benzene in the solution, we first need to convert the mole fraction of benzene to mass fraction using the molecular weights of benzene and toluene. Then, we can use the formula: Mass percent = (mass fraction of benzene / total mass of solution) x 100 Given the mole fraction of benzene as 0.40, we can use this information to determine the mass fraction and then calculate the mass percent of benzene in the solution.