A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?

Answer 1

Balanced equation first.

HNO3 + NaOH >> NaNO3 + H2O

Now, Molarity = moles of solute/volume of solution ( find moles HNO3 )

0.800 M HNO3 = moles/2.50 Liters

= 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH )

2 moles NaOH (39.998 grams NaOH/1mole NaOH)

= 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )