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3m/s squared

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Q: A player uses a hockey stick to increase the speed of a 0.200kg hockey puck by 6 ms in 2 seconds. how much did the hockey puck accelerate how much force did the puck exert on the hockey stick how much?
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A player uses a hockey stick to increase the speed of a 0.200kg hockey puck by 6ms in 2 seconds How much did the hockey puck accelerate?

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A player uses a hockey stick to increase the speed of a 0.200kg hockey puck by 6 ms in 2 seconds How much did the hockey puck accelerate?

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A player y stick to increase the speed of a 0.200kg hockey puck by 6ms in 2 seconds how much did the hockey puck accelerate how much force was exerted on the puck?

6 m/s in 2 seconds. v = at velocity equals acceleration times time. 6 = 2a so a=3m/s2 This question is independent of mass.


A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 ms in 2 seconds how much force did the puck exert on the hockey stick?

what a stupid question!!


A player uses a hockey stick to increase the speed of a 0 200kg hockey puck by 6 m s in 2 seconds How much did the hockey puck accelerate?

Mass of the item doesn't matter. The acceleration is 3 m/s2 (6 m/s divided by 2 seconds). However, mass comes into play when calculating force; if the mass is 0.200 kg, it would take a force of 0.600 Newtons (0.200 kg x 3 m/s2).


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A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6m s in 2 seconds how much did the hockey puck accelerate?

You don't need the mass of the puck to calculate the acceleration.Acceleration = (change in speed) divided by (time interval) = 6/2 = 3 meters per second2Since the acceleration of gravity on earth is 9.78 m/s2 , the puck's acceleration was 3/9.78 = 0.307 of one G .


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A player uses a hockey stick to increase the speed of a 0.200kg hockey puck by 6 ms-1 in 2 seconds how much did the hockey puck accelerate how much force did the puck exert on the hockey stick?

a = Δv/t = (6 m/s)/(2 s) = 3 m/s2F = ma = (0.200 kg)(3 m/s2) = 0.6 NThe answer is correctly given to one significant digit.Symbols:Δ = "change in"Units:m = meterss = secondsN = newtonsVariables:d = displacement (m)t = time (s)v = velocity (m/s) = Δd/ta = acceleration (m/s2) = Δv/tm = mass (kg)F = Force (N) = ma


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A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6m s in 2 seconds how much force was exerted on the puck?

Since Force=mass x acceleration (and acceleration=velocity/time), hence force= 0.2 x(6/2)=0.2 x 3=0.6N


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How much force did the puck exert on the hockey stick at 0.200kg in a 6ms in 2 seconds?

Not that much actually.