That's the basic calculation:
V0 - the starting velocity/speed (m/s)
a - acceleration (m/s)
t - duration of the acceleration (s)
v=v0+a*t
in this case if the puck wasn't moving and you have accelareted it for 2 seconds
v=0+6*2=12 (m/s)
If I missunderstood your question then let me apologize for it.......
a = Δv/t = (6 m/s)/(2 s) = 3 m/s2
F = ma = (0.200 kg)(3 m/s2) = 0.6 N
The answer is correctly given to one significant digit.
Symbols:
Δ = "change in"
Units:
m = meters
s = seconds
N = newtons
Variables:
d = displacement (m)
t = time (s)
v = velocity (m/s) = Δd/t
a = acceleration (m/s2) = Δv/t
m = mass (kg)
F = Force (N) = ma
According to Newton or one of those old dead guys, the opposing force will be equal. So why doesn't the stick go flying 90-miles-an-hour in the opposite direction??? Only because it has a greater mass and there's a hockey player hanging on to it. 6 N
Force equals mass times acceleration.
Since the puck's velocity increased by 6 meters per second in 2 seconds its acceleration is 3 meters per second squared (6/2).
Its mass is 0.2 kg.
Therefore force = 0.2 * 3
Force = 0.6 newtons
Do your own homework, kid.
The steps to follow are:
I asked for help dummy. you weren't even any help. so go f off
It's like two calculations bro.
6 m/s
To accelerate to zero, you need to accelerate at -3m/s^2
The puck has a mass of 0.5 kg.
That's a total of -1.5N of force
3m/s squared
There is no answer to your question without knowing the direction of the velocity and of the force application.
Because you reach maximum velocity.
It's zero
What is the angular velocity of a 6-foot pendulum that takes 3 seconds to complete an arc of 14.13 feet? Use 3.14 for p...
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
Acceleration is the time rate of change of velocity. If velocity is constant, then acceleration is zero. Note: "100 km per h for 10 seconds" is a constant speed, but not necessarily a constant velocity, since we're told nothing about the direction. If the car moves in a perfectly straight line during those 10 seconds, then its velocity is constant. If it makes a curve, then its velocity is not constant even though its speed is, and there is acceleration.
In the case of constant velocity (or speed), velocity = distance / time.
The answer is very simple. The words "constant velocity" are the definition of zero acceleration.
There is no answer to your question without knowing the direction of the velocity and of the force application.
Because you reach maximum velocity.
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.
Constant velocity is a measure of distance traveled per unit of time at a uniform speed, such as miles per hour or feet per second. Constant acceleration is a measure of a continuing increase in velocity per unit of time, as when a car speeds up from 30 miles per hour to 40 miles per hour in 5 seconds, then from 40 miles per hour to 50 miles per hour during the next 5 seconds. It will then have had a constant acceleration of 10 miles per hour per 5 seconds.
It's zero
What is the angular velocity of a 6-foot pendulum that takes 3 seconds to complete an arc of 14.13 feet? Use 3.14 for p...
Constant speed and constant velocity
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
10 x 30 = 300 metres.