In the case of constant velocity (or speed), velocity = distance / time.
The velocity = (location at 40 seconds - location at 20 seconds)/20 in the direction in which the object is moving.
Velocity = Distance/Time = 28/1.4 = 20 m/s
The ball continues to rise until its upward speed decreases to zero. Since gravity adds 9.8 meters per secondto its downward speed every second, it will continue moving upward for (20/9.8) = 2.0408 seconds (rounded).After it peaks and begins falling, it will return to the elevation from which it was launched in the same length of time.The total time from launch to catch is (20/9.8) x 2 = 4.0816 seconds (rounded).(We don't know about additional time to fall to the ground, because we don't know exactly how highthe hand was when the ball was launched.)
Height = H0 + V0 T +1/2a T2H0 = height when released = +5V0 = velocity when released = 20 up = +20a = acceleration of gravity = 32.2 down = -32.2When the ball hits the ground, "Height" = 05 + 20 T - 16.1 T2 = 0Easier . . . 16.1 T2 - 20 T - 5 = 0Quadratic formula: T = 1/32.2 [ 20 +/- sqrt(400 + 322) ]T = (20 +/- 26.87) / 32.2T = -0.213 secondsT = 1.456 seconds (rounded)
There is no answer to your question without knowing the direction of the velocity and of the force application.
4 m/s
The speed of the the object is 20/5 = 4 metres per second.In order to answer the question in terms of velocity, it is necessary to know the direction of motion because velocity is a vector.
Velocity (or Speed) = Distance ÷ Time Toni's speed is therefore 100 ÷ 20 = 5 feet per second. Distance = Velocity x Time In 25 seconds, Toni walks, 5 x 25 = 125 feet.
The idea is that you should: a) Calculate the change in velocity. b) Divide this change by the time. This gives you the average acceleration over the 20 seconds, in this case.
A rotating merry go round has a radius of 30 feet. If it completes one revolution in 20 seconds, find the velocity of the outer edge.
20 meters per second is the speed--velocity would require direction data, as well. Velocity is a vectored quantity.
The answer for that one is 500 m/s