Since it is a regular pentagon, all the sides are the same length.
Hence the pentagonal centre is the same as the circle centre.
This makes for 5 Isosceles triangles, that construct the pentagon.
Taking the centre divide the centre angle of 360 degrees by '5' . Hence
360/5 = 72 degrees for each pentagonal Isosceles triangle.
Using the Isoscelean Law the other two angles are (180 - 72) / 2 = 54 degrees.
Hence the internal angles of the pentagon are each 108 degrees.
Hope that helps!!!!!
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assuming this is a regular pentagon (all five sides are equal length) the center is the intersection of the intersection of perpendicular bisectors of each side and should also be the center of the circle in which it is inscribed
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A pentagon is a five sided geometrical figure; if the pentagon fits exactly inside some other geometrical figure (such as a circle) then it can be said to be inscribed in that figure.
The measure of an exterior angle of an equiangular pentagon is 72 degrees. An equiangular pentagon is a regular pentagon that has five equal sides and five equal angles. An interior angle of a pentagon is equal to 108 degrees.
Nothing particular. One of the properties of regular polygons - however many sides - is that it can have a circle inscribed in it.
The radius of a circle inscribed in a regular hexagon equals the length of one side of the hexagon.
If the distance from the centre of the pentagon to a vertex is r cm then the length of the arc is 0.4*pi*r cm
I assume you mean a polygon inscribed in a circle. It is regular if all its sides and angles are equal.
If you know the length of the side of the (regular) hexagon to be = a the radius r of the inscribed circle is: r = a sqrt(3)/2
circumscribed means the polygon is drawn around a circle, and inscribed means the polygon is drawn inside the circle. See related links below for polygon circumscribed about a circle and polygon inscribed in a circle.
The circle has a smaller area than the polygon.