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A rock is thrown upward at an angle what happens to the vertical component of its velocity as it rises?
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A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
What is the vertical velocity at the top of the path of a projecticle thrown striaght up or launched at an angle?
At the top of the path, the projectile stops rising and starts falling. The vertical component of velocity at that point is zero.
How are the horizontal velocity and the vertical velocity of thrown objects related?
If you can ignore air resistance, they're not. Neither component has any influence on the other one unless the object is acting as an airfoil.
Will the object that is dropped hit the ground before an object that is that it is thrown horizontally from the same height?
No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
When will objects thrown upward start to go down?
When the vertical component of their velocity has dwindled to zero because of the acceleration of gravity.
What is the vertical velocity at the top of the path of a projecticle thrown striaght up or launched at an angle?
At the top of the path, the projectile stops rising and starts falling. The vertical component of velocity at that point is zero.
How are the horizontal velocity and the vertical velocity of thrown objects related?
If you can ignore air resistance, they're not. Neither component has any influence on the other one unless the object is acting as an airfoil.
A banana is thrown straight out so it has both horizontal and vertical velocity After 1 second, what is its vertical velocity?
9.8
How can you used trigonometry in projectile motions?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
Will the object that is dropped hit the ground before an object that is that it is thrown horizontally from the same height?
No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.
Is an object that is dropped will hit the ground before an object that is thrown horizontally from the same height?
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
How fast must an object be thrown up if it is to stay in the air for 5 seconds before hitting the ground again?
An object can be thrown vertically upwards or at an angle to the ground, in both cases it is needed that time of flight be 5 seconds. This means it's time of ascent (going up) is 2.5 seconds and time of descent(coming down) is also 2.5 seconds. So, it reaches highest point 2.5 seconds after it is thrown. At highest point the vertical component of velocity1 of the object becomes zero for an instance.Now, kinematics equation can be used to solve this.v = uy - g*twhere v is final velocity at top =0. uy is initial vertical velocity1. g is accleration due to gravity(9.8ms-2). t is time of ascent.putting values we get.0 = uy - 9.8 * 2.5or uy = 24.5 ms-1So we need to throw an object with vertical velocity = 24.5 meters per second so that it remains in air for 5 seconds.1. If object is thrown at an angle then vertical component of velocity of projection is taken.If object is thrown vertically upwards then vertical component of velocity of projection issame as velocity.vertical component of velocity of projection(uy) = u*sin(θ), where u is velocity of projectionand θ is angle of projection with respect to horizontal.2. Accleration due to gravity is different for different places. 9.8ms-2 is an approximatevalue.3. Here, air resistance and wind speeds have been neglected as they make the calculation verytedious and they are always varying from time to time and place to place.
