If the sample is at 100 0C, at standard pressure, no supplementary heating is necessary.
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A similar but more detailed take:
Water's latent heat of vaporization is listed as 2,260 kJ/kg = 2.26 J/gram
Since your sample of H2O is in equilibrium right now and sitting there with the uniform
temperature of 100°C, it's ready to vaporize the next time some energy is added,
no matter how little.
Let's say an additional 0.1 Joule comes along and is absorbed. Some little tiny
mass of water ... 0.1/2.26 gram in this example ... must change phase and turn
to vapor. There will be a small blurp in the beaker as the vapor rises, the
surface of the liquid will be disturbed, and anyone watching will report that
it has 'boiled'.
To change the phase of the entire 46.0 grams and turn it to vapor would require
46 x 2.26 = 103.96 Joules.
46 x 58 x 4.2 J/g K = 11,205.6 joules. but it will still be ice at 0oC. it requires additional energy to transform it into water
The heat is 5,624 kJ.
5.60 x 10^3
1.29 x 10^3
The specific heat of liquid water is approximately 4.18 Joules per gram degree Celsius (J/g°C).
To find the mass of the iron sample, you need to know the specific heat capacity of iron. Given that the heat energy required to raise the temperature is 562 Joules, you can use the formula: heat energy = mass x specific heat capacity x temperature change. With the specific heat capacity of iron (0.45 J/g°C), you can calculate the mass of the iron sample.
To calculate the specific heat of a compound like NaOH, you would need to know the mass of the compound and the energy required to change its temperature by a certain amount. The formula to calculate specific heat is: specific heat = (energy applied)/(mass * temperature change). Once you have these values, you can plug them into the formula to find the specific heat of the compound.
The amount of thermal energy needed to raise the temperature of 1 kg of a material by 1 degree Celsius is known as the specific heat capacity of the material. It varies depending on the material, but for water, which has a specific heat capacity of 4.184 J/g°C, it would take 4.184 J of energy to raise the temperature of 1 kg of water by 1 degree Celsius.
The amount of energy required to heat a sample of water can be calculated using the formula: energy = mass x specific heat capacity x temperature change. Given that the specific heat capacity of water is 4.18 J/g°C, and assuming a temperature change of 1°C, the energy required would be 46 g x 4.18 J/g°C x 1°C = 192.28 J.
The amount of energy needed to change the temperature of a substance is known as heat. It is measured in units such as calories or joules. It takes a specific amount of heat energy to raise the temperature of a substance by a certain number of degrees Celsius.
The temperature of the ocean must be 80 degrees or 26 celsius in order for a hurricane, typhoon or a cyclone form.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
Quantity of Energy= mass x temperature change x specific heat capacity For example: Find the amount of energy needed to raise the temperature of 0.20 kg of lead by 15 degree Celsius if the specific heat capacity of lead is 0.90 J/g degree Celsius. Answer: J=200g x 15 degree Celsius x 0.90 J/g degree Celsius = 2700 J
The specific heat of liquid water is approximately 4.18 Joules per gram degree Celsius (J/g°C).
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
Is the amount of energy that is required to change the temperature of 1kg of a substance by 1 degree Celsius with no state change.
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?
Specific heat is measured in units of energy per unit mass per degree Celsius (J/kg°C or cal/g°C). It indicates the amount of heat energy required to raise the temperature of a specific amount of a substance by one degree Celsius.
90,000
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
25degres celsius has more thermal energy