If the sample is at 100 0C, at standard pressure, no supplementary heating is necessary.
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A similar but more detailed take:
Water's latent heat of vaporization is listed as 2,260 kJ/kg = 2.26 J/gram
Since your sample of H2O is in equilibrium right now and sitting there with the uniform
temperature of 100°C, it's ready to vaporize the next time some energy is added,
no matter how little.
Let's say an additional 0.1 Joule comes along and is absorbed. Some little tiny
mass of water ... 0.1/2.26 gram in this example ... must change phase and turn
to vapor. There will be a small blurp in the beaker as the vapor rises, the
surface of the liquid will be disturbed, and anyone watching will report that
it has 'boiled'.
To change the phase of the entire 46.0 grams and turn it to vapor would require
46 x 2.26 = 103.96 Joules.
46 x 58 x 4.2 J/g K = 11,205.6 joules. but it will still be ice at 0oC. it requires additional energy to transform it into water
The heat is 5,624 kJ.
5.60 x 10^3
1.29 x 10^3
This is the necessary energy to raise the temperature of 1 gram with 1 kelvin.
Specific heat is the measure of energy it takes to raise a unit mass in temperature by one degree Celsius. When measuring a compound that is water soluble, heat it separately to a specific range, then use the liquid to calculate the amount of heat that was used.
q(joules) = mass * specific heat * change in temperature q = (500 grams H2O)(4.180 J/goC)(100o C - 20o C) = 1.7 X 105 joules ================add this much heat energy to the water
The temperature of the water would be 4.58333 degrees Celsius higher.
Specific heat capacity is the amount of energy or heat required to raise the temperature of a unit mass of a substance by one kelvin. So if the specific heat capacity is high then you would require more energy or heat to raise its temperature. The specific heat capacity does not really have anything to do with how much you can increase an objects temperature. IT HAS TO DO WITH THE ENERGY NEEDED TO INCREASE THE TEMPERATURE.
The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
specific heat content is calculated by the joules of energy required to change the temperature of one cubic centimeter of the material 1 degree Celsius.
The temperature of the ocean must be 80 degrees or 26 celsius in order for a hurricane, typhoon or a cyclone form.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
Quantity of Energy= mass x temperature change x specific heat capacity For example: Find the amount of energy needed to raise the temperature of 0.20 kg of lead by 15 degree Celsius if the specific heat capacity of lead is 0.90 J/g degree Celsius. Answer: J=200g x 15 degree Celsius x 0.90 J/g degree Celsius = 2700 J
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
Is the amount of energy that is required to change the temperature of 1kg of a substance by 1 degree Celsius with no state change.
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?
90,000
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
25degres celsius has more thermal energy