The answer this question you first have to find the molar mass of glucose:
Carbon 12.01 g (Atomic Mass of element) * 6 (amount of atoms in glucose)
Hydrogen 1.008 g * 12
Oxygen 16.00 g *6
Add the values together to get the molar mass. 180.56 g
180.56 is the molar mass of glucose in 1 mol.
You can set up a proportion to solve this particular problem.
180.56 g ? g
------------ = -------------
1 mol 0.500 mol
The answer would be 90.078 g.
molar mass glucose = 180 g/mol
90 g x 1 mol/180 g = 0.5 moles glucose
0.5 moles glucose x 6.02x10^23 molecules glucose/mole glucose = 3.01x10^23 molecules of glucose
3.01x10^23 molecules of glucose x 6 atoms C/molecule = 18.06x10^23 atoms = 1.8x10^24 carbon atoms
The molar mass of glucose (C6H12O6) is 180,16 g.
The molar mass of glucose is approximately 180 g/mole. More precisely, it is 180.16 g/mole.
The chemical formula for glucose is C6H12O6.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
The chemical formula for glucose is C6H12O6.
C6h12o6 = glucose and h2o = water
The molar mass of glucose is 180,16 g.
The molar mass of glucose is 180.15588 g/mol.
C6H12O6 (molar mass: 180.16 g/mol). It may refer to glucose, hexoses, and other subtsances.
C6H12O6 is the chemical formula of glucose (not sucrose !).The mass of 4.00 moles of glucose is 720,64 g.
Well first you should determine the molecular mass of your glucose molecule, then you should divide the molecular mass of all the carbon by this, if I recall correctly. Should look something like (12X6) / ((6X12)+(12X1)+(6X16)) All multiplied by 100 to make it a percentage. Gives something like 40% which sounds like the right answer looking at the question.
The chemical formula for glucose is C6H12O6.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
number of moles = mass/molar mass n= m/Mr n=512/ (12.01*6)+(1.008x12)+(16x6) n= 512/180.156 n= 2.842 (rounded to three decimal places, otherwise; 2.841981394)
The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
The chemical formula for glucose is C6H12O6.
Te chemical formula of glucose is C6H12O6.
C6h12o6