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We can use the ideal gas equation (PV=nRT).

I like to use .08206 as my R constant, so I must convert torr into atmospheres. In addition, temperature must be converted into Kelvin by adding 273 to your temperature in Celsius in order for this to work.

285.5 torr / (760 torr/ATM) = .376 ATM.

Plugging in all the information into PV=nRT;

(.376 ATM)(8.744 L)=n(.08206)(320 K)

n=(.376 ATM)(8.744 L) / (.08206)(320 K)

n=.125 mol N2(g)

This can also be done with van der Wall's non-ideal gas equation, but it involves cubic equations that can get quite ugly and they yield an extremely close value to .125 moles.

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Q: A sample of nitrogen gas is confined in a 8.744 L container at 2.855 x 102 torr and 47 oC How many moles of gas are present in the sample?
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