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Answered 2008-10-28 15:47:42

0.063 g of oxalic acid * (1 mol H2C204*2H2O / 126.07 g) = 0.0004997 mol H2C2O4*2H2O 0.0004997 mol H2C204 / 0.250 L = 0.001999 M of H2C2O4

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molar mass H2C2O4x2H2O = 2+24+64+36 = 126 g/molemoles = 2.38 g x 1mol/126 g = 0.0189 molesmolarity = 0.0189 moles/0.200 L = 0.0944 M


The name of the compound H2C2O4 is oxalic acid.


The name of the compound H2C2O4 is oxalic acid.


molar mass H2C2O4 = 2*1 + 2*12 + 4*16 = 90.0 g/mol = 90.0 mg/mmol25.5 mg in 1.0 ml = 25.5/90.0 mmol/ml = 0.283 mmol/ml = 0.283 mol/L = molarity oxalic acid



oxalic acid- joana cel


Oxalic acid is an organic compound, a diprotic acid, with the molecular formula H2C2O4.


H2C2O4, It is HOOC-COOH


Oxalic acid has covalent bonds.



H2C2O4 + 2KOH --> K2C2O4 + 2H2O


The conjugate acid of HC2O4- is oxalic acid, H2C2O4.


Oxalic acid has the chemical formula H2C2O4. It is a strong dicarboxylic acid occurring in many plants and vegetables.


C2O4-2 Oxalate (a negative 2 ion). Oxalic acid=H2C2O4


It most certainly would affect the molarity of oxalic acid. When you change the volume, i.e. dilute, you decrease the molarity. It is the number of moles that doesn't change.


Oxalic acid + Sodium Hydroxide ----> Sodium Oxalate + WaterH2C2O4 + 2 NaOH ----> Na2C2O4 + 2 H2O


Well, when I looked online for the formula for oxalic acid, it said it was H2C2O4. If this is correct the equation would be H2C2O4 + Al(OH)3 --> H2O..... Something... Im not sure about that last part because the oxalic acid formula doesnt seem right to me... But it would be a double-displacement reaction.


A great golf ball cleaning solution contains oxalic acid.


Rust is Fe2O3 ....it can not be removed by 1.HCl 2.H2So4 3.Edta..... but can remove by Oxalic Acid H2C2O4 Fe2O3(s) + 6 H2C2O4(aq) → 2 Fe(C2O4)3 3−(aq) + 3 H2O(l) + 6 H+(aq)


H2C2O2 is a dialdehyde by the name glyoxal. And it is neutral. However, H2C2O4 is oxalic acid and is weakly acidic.


the pH will decrease slightly as oxalic acid is a weak acid.


H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l)


Acetic acid (HC2H3O3) Oxalic acid (H2C2O4) Phosporic (H3PO4)


Yes. With the exception of carbonic acid (H2CO3), oxalic acid (H2C2O4), and their salts compounds of carbon and hydrogen are always organic.


how to prepare 0.5M of oxalic acid powder



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