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75m/s
The momentum product can be the same with different velocities; m1V=m2rV thus m1/m2=r ratio with V1=rV1.
(Momentum) = (mass) x (velocity) If you know the momentum and the mass, you can find the velocity. Do you know how to do algebra? (velocity) = (Momentum) / (mass) = (30,000 kg m/s) / (400 kg) = 75 m/s
Angular momentum about the axis of rotation is the moment of linear momentum about the axis. Linear momentum is mv ie product of mass and linear velocity. To get the moment of momentum we multiply mv by r, r the radius vector ie the distance right from the point to the momentum vector. So angular momentum = mv x r But we know v = rw, so angular momentum L = mr2 x w (w-angular velocity) mr2 is nothing but the moment of inertia of the moving body about the axis of rotation. Hence L = I w.
Yes, "velocity" is a vector so it not only has magnitude but also direction. By convention, an object moving from left-to-right or upward is moving in a positive direction while an object moving right-to-left or downward is moving in a negative direction. "Speed" is a related term but it is a scalar. As such, it has only magnitude. A speed cannot be negative.
75m/s
75 m/s "Apex"
Momentum = mass x speedSince Spaceship-#1 is not moving, it has no momentum. Their combined momentumis that of Spaceship-#2 alone.Momentum = mass x speed = 200 x 10 = 2,000 kilogram-meters per second.
The momentum product can be the same with different velocities; m1V=m2rV thus m1/m2=r ratio with V1=rV1.
Because speed is the magnitude of the velocity vector. The velocity consists of the speed and the direction, and the whole thing can be embodied in a 3D vector. If you like the velocity is the magnitude (the speed), which is a scalar (just a real number), multiplied by a unit vector in the right direction.
Momentum =mv. The lioness has a momentum of 180 x 16 = 2880 kg m per s to the right.
(Momentum) = (mass) x (velocity) If you know the momentum and the mass, you can find the velocity. Do you know how to do algebra? (velocity) = (Momentum) / (mass) = (30,000 kg m/s) / (400 kg) = 75 m/s
Angular momentum about the axis of rotation is the moment of linear momentum about the axis. Linear momentum is mv ie product of mass and linear velocity. To get the moment of momentum we multiply mv by r, r the radius vector ie the distance right from the point to the momentum vector. So angular momentum = mv x r But we know v = rw, so angular momentum L = mr2 x w (w-angular velocity) mr2 is nothing but the moment of inertia of the moving body about the axis of rotation. Hence L = I w.
Momentum. Momentum is mass x velocity. Velocity is speed in a direction. Even if the bus changes direction, you still have momentum in the original direction until some force pushes you in another direction. That takes a moment in a car or bus, so until your momentum is that of the bus, you'll still be going in a slightly different direction, which happens to seem 'outwards'.
Yes, "velocity" is a vector so it not only has magnitude but also direction. By convention, an object moving from left-to-right or upward is moving in a positive direction while an object moving right-to-left or downward is moving in a negative direction. "Speed" is a related term but it is a scalar. As such, it has only magnitude. A speed cannot be negative.
Yes. The ball is moving, right? It has both momentum (mass times velocity) and kinetic energy (one-half the mass times the velocity squared). When you hit the ball with the bat, the energy of the ball is transferred to the bat, and the bat imposes its own energy and momentum to the ball.
There are different types of momenta. What you are referring to is LINEAR momentum. Linear momentum is the product of an object's mass and linear (along a straight line: translational motion) velocity and is usually represented by 'p' : p = mv. Keep in mind that it is a vector quantity (has a magnitude and direction). Momentum represents the "amount of motion" of an object. Say you have two masses, m1 = m and m2 = 2m, so that m2 is twice as massive as m1. m1 is moving to the right at a linear velocity v1 = 2v and m2 is moving to the right at a linear velocity v2 =v. What are their linear momenta? Well, p1 = m1 v1 = 2mv and p2 = m2 v2 = 2mv, so that p1 = p2. So, although both objects have DIFFERENT linear velocities and DIFFERENT masses, their linear momenta ("amount of motion") for this case are the same. Now, if instead m1 is moving to the right at v1 = 3v and m2 is moving to the right at v2 = v, then: p1 = m1 v1 = 3mv p2 = m2 v2 = 2mv Although m1 is the smaller mass, it has a larger "amount of motion" compared to m2 for this case, because it's linear velocity is larger than the former case.