Using Hooke's Law Equation, k = F / displacement,
k = 720N / 0.15m
k = 4800N/m
When a 60kg mass is hung on it,
F = ma = 60kg x 9.98m/s^2
F = 598.8N
Again, using Hooke's,
displacement = F / k
displacement = 598.8N / 4800N/m
displacement = .12475m
displacement = 12.475cm
The spring constant can be calculated using Hooke's Law, which states F = kx, where F is the force, k is the spring constant, and x is the displacement. Rearranging the formula to solve for k gives k = F/x. Plugging in the values gives k = 60 N / 1.5 m = 40 N/m.
Step 1
Write out the information you already know:
Fapp= 60 N [right] (or whichever direction the force applied is), therefore
Fx= -60 N [right]
x= 1.5 m
Step 2
Use the equation:
Fx= -kx
-60= -k(1.5)
k= 40 N/m
The force applied by the spring can be calculated using Hooke's Law, which states that the force is equal to the spring constant (k) multiplied by the displacement (x). Plugging in the values, the force would be 25 N/m * 0.25 m = 6.25 N.
The spring constant is 263.6363... repeating Newtons per metre.
To find the equivalent spring constant, you need to know the distance from the point where the force is applied to the axis of rotation. If this distance is 0.10 meters, then the equivalent spring constant would be 5 N/m (k = τ/θ).
The spring constant is 200 N/m. This is found by using Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension, with the constant of proportionality being the spring constant.
Just divide the force by the amount of stretch.
The force applied by the spring can be calculated using Hooke's Law, which states that the force is equal to the spring constant (k) multiplied by the displacement (x). Plugging in the values, the force would be 25 N/m * 0.25 m = 6.25 N.
The spring constant is 263.6363... repeating Newtons per metre.
To find the equivalent spring constant, you need to know the distance from the point where the force is applied to the axis of rotation. If this distance is 0.10 meters, then the equivalent spring constant would be 5 N/m (k = τ/θ).
The spring constant of an elastic material is a measure of how stiff the material is. It represents the force required to stretch or compress the material by a certain amount. It is typically denoted by the symbol k and has units of force per unit length or force per unit deformation.
Just divide the force by the amount of stretch.
24.5 newtons per meter
When a pulling force is applied to a spring, it stretches due to the tension created in the spring's material. The spring elongates in the direction of the applied force until the force is removed. The amount of stretching is proportional to the force applied, as described by Hooke's Law.
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
Most force meters use a spring mechanism inside them. The force applied to the meter stretches or compresses the spring, which then generates a reading calibrated to measure force. Some force meters also use strain gauges or piezoelectric sensors to measure force.
It takes a larger force to compress or pull a spring the same distance as a spring with a smaller spring constant. This is shown in Hooke's law. x=F/k k---is the spring constant F---is the force applied to the spring x is the distance the spring has been compressed
The spring constant is a characteristic of the spring itself and represents its stiffness, regardless of the applied force or elongation. It is a constant value for a particular spring and is not influenced by external factors such as the amount of force applied or the degree of elongation.
The spring scale got its name because it uses a spring to measure force or weight. The spring within the scale stretches or compresses based on the applied force, allowing for accurate measurement of the weight of an object.