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A spring stretches 1.5 meters when a force of 60 N is applied to it What is the spring constant?
Wiki User
∙ 13y ago
Using Hooke's Law Equation, k = F / displacement,
k = 720N / 0.15m
k = 4800N/m
When a 60kg mass is hung on it,
F = ma = 60kg x 9.98m/s^2
F = 598.8N
Again, using Hooke's,
displacement = F / k
displacement = 598.8N / 4800N/m
displacement = .12475m
displacement = 12.475cm
Wiki User
∙ 11y ago
Wiki User
∙ 13y agoStep 1
Write out the information you already know:
Fapp= 60 N [right] (or whichever direction the force applied is), therefore
Fx= -60 N [right]
x= 1.5 m
Step 2
Use the equation:
Fx= -kx
-60= -k(1.5)
k= 40 N/m
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What is the force applied by a spring as it stretches upward 0.25 meters and has a k value of 25 newtons per meter?
6.3
A spring stretches 11 centimeters from its equilibrium position when an object weighing 29 newtons is hung from it. What is the spring constant?
The spring constant is 263.6363... repeating Newtons per metre.
What is spring constant of an elastic material?
Spring constant of an elastic material is the force applied per unit extension.
What is the spring constant when it is stretched 1.5 meters when a force of 60 N is applied to it?
Just divide the force by the amount of stretch.
Does the spring constant depend on applied force or elongation?
the relation between force (F) and elongation (x) is F = kx where k is the spring constant. The stiffer the spring, the higher the force needed to get a certain elongation; or, for a given force, the elongation will be less for a stiffer spring
What is the force applied by a spring as it stretches upward 0.25 meters and has a k value of 25 newtons per meter?
6.3
A spring stretches 11 centimeters from its equilibrium position when an object weighing 29 newtons is hung from it. What is the spring constant?
The spring constant is 263.6363... repeating Newtons per metre.
What is spring constant of an elastic material?
Spring constant of an elastic material is the force applied per unit extension.
A 75 kg mass attached to a vertical spring stretches the spring 30 m what is the spring constant?
24.5 newtons per meter
What is the spring constant when it is stretched 1.5 meters when a force of 60 N is applied to it?
Just divide the force by the amount of stretch.
What is the spring constant of a spring?
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
Why does a large spring constant indicate a stiff spring?
It takes a larger force to compress or pull a spring the same distance as a spring with a smaller spring constant. This is shown in Hooke's law. x=F/k k---is the spring constant F---is the force applied to the spring x is the distance the spring has been compressed
Does the spring constant depend on applied force or elongation?
the relation between force (F) and elongation (x) is F = kx where k is the spring constant. The stiffer the spring, the higher the force needed to get a certain elongation; or, for a given force, the elongation will be less for a stiffer spring
If a 30kg weight is hanging on a spring and it stretches 0.5m what is the spring constant of the spring?
Hooks law: F=-x*K F=Force x=distance = 0.5m K=constant F=mass*9.81 = 30*9.81=aaaa [N] aaa = -0.5 * K => K = something
What is the formula for spring stiffness?
The constant spring stiffness formula is the force applied to the spring equal to the stiffness times the distance it moved. F=kx. Depending on where your axis are, it could be negative.
Why does the suspended spring stretch more at the top than at the bottom?
There is more force applied to the top of the spring than the bottom, because the whole spring is hanging from the top, but only a small part is hanging from near the bottom. The larger force stretches the spring more.
What is the relationship exists between the force exerted on a spring and the resulting elongation of the spring?
That is called the Spring Constant. It describes the amount of deformation of the spring, either stretch or compression, in units of distance deformed for each unit of force applied.
