1.8%
It depends on the calibration of the instrument you are measuring with.
7.28
90%
3.531%
The goal of area normalization is to correct for sample size discrepances, that in a negative way affects the sum of all measured solutes. Example If 4 peaks are being measured and the sum total area of all peaks turns out to be less than or greater than 100 percent, Normalization corrects for this and shifts all peaks by the needed percentage to bring them to a sum of 100 percent. If the sum total equals 90 percent, then normalization will shift up each individual peak 10 percent, which will bring the sum up to 100 percent..
It is approx 12.8%.
It depends on the calibration of the instrument you are measuring with.
A percentage error for a measurement is 100*(True Value - Measured Value)/True Value.
Percent error is calculated by the measured value and the acceped value. For example, if you measure a piece of paper and decide it is 8.45in long, that is your measured value. The package says it is 8.5in long, so it is the accepted value. The formula for percent error is |measured value - accepted value| divided by accepted value ALL times 100.
Kinetic Energy = 1/2 (mass) (velocity)2Measurement of mass is in error by 3%.Measurement of velocity is in error by 4%.If both are low, then KE is measured as(True KE) x (.97) x (.96)2 = 0.894 TKE = 10.6% low.If both are high, then KE is measured as(True KE) x (1.03) x (1.04)2 = 1.114 TKE = 11.4% high.If one is high and the other low, then the net error is in between these limits.
When giving the result of the measurement, its important to state the precision or estimated uncertainty, in the measurement. The percent uncertainty is simply the radio of the uncertainty to the measured value, multiplied by 100. 4.19m take the last decimal unit, is 9 but with value of 1/100 .01 is the uncertainty Now, .01/4.19 x 100 % = 0.24%
10 percent of 60 students is 6 students.
Approximately 56% of college students in the United States are women. This percentage has been steadily increasing over the years, with women now outnumbering men in higher education enrollment.
Percent of an objects mass is expressed in terms of its weight. Percent of an objects volume is expressed in terms of its size.
72 is 80 percent of 90.
Measurement error: obviously!
That depends what the measurement is one percent of.