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A very long wire carrying a conventional current of 4.1 amperes is straight except for a circular loop of radius 6.4 cm Calculate the approximate magnitude and the direction of the magnetic field at?
Wiki User
∙ 13y ago
Since the figure is both a straight wire as well as a loop, you would use the equations:
Bwire= (1e-7)* [(2I)/(r)]
Bloop= (1e-7)* [(2pi*R^2*I)/((z^2+R^2)^(3/2))], where z=0 in this case
You add these two equations together to get the correct answer:
Bloop + Bwire = approximate magnitude of the magnetic field
(1e-7)* [(2pi*R^2*I)/((R^2)^(3/2))] + (1e-7)* [(2I)/(r)] =
(1e-7)* [(2pi*.064^2*4.1)/((.064^2)^(3/2))] + (1e-7)* [(2*4.1)/(.064)] =
|B| = 4.0251e-5 + 1.2812e-5
|B| = 5.30641e-5
Direction is out of the page
Wiki User
∙ 13y ago
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