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A weather balloon full of helium with a volume of 47.1 L at 22oC is sitting inside an aircraft hangar The temperature of the hangar increases to 33oC Which equation would be easiest to use to find t?
Wiki User
∙ 15y ago
(v1/t1) = (v2/t2)
Wiki User
∙ 15y ago
alexus lee
Wiki User
∙ 12y ago(v1/v1)(v2/v2)
K Clemons
A weather balloon full of helium with a volume of 27.1 L at 28°C is sitting
inside an aircraft hangar. The temperature of the hangar increases to 33°C.
Which equation would be easiest to use to find the new volume of the
balloon?
VICENTE
(V1/T1)=(V2/T2)
GSoda
(V1/T1)=(V2/T2).
Laury Homenick
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If you have 45L of helium in a balloon at temperature of25c and increased the temperature of the balloon to 55c what will the new volume of the balloon be?
49.5
Consider a balloon that is being inflated As the balloon increases in size the area of its surface increases Each time the balloon's diameter doubles what do you expect for the change in the area?
For any geometric figure, surface area is proportional to (linear dimensions)2 .As the balloon's diameter doubles, its area increases by the factor of (2)2 = 4 .
If the temperature of a balloon was to decrease what else would change?
The particles in the balloon slow down as the temperature decreases cause it to deflate
Does temperature affect the maximum size that you can inflate a balloon?
When the temperature is colder the particles in the balloon travel slower, making the balloon not able to increase in size it decreases.When the temperature is hot it allows the balloon to expand because the particles in the balloon are moving rapidly. in conclusion the the cold makes the balloon decrease in size and the heat allows it to expand.
Four balloons of equal size are filled with hydrogen at room temperature hydrogen at 0 degrees clean air at room temperature and clean air at 0 degrees which balloon will shrink the fastest?
You would think that the balloon at the lowest temperature would shrink the fastest due to the simple ideal gas law equation. PV=nRT HOWEVER the temperature is not the determining factor in this case. Hydrogen leaks through rubber and the greater the temperature the faster the leakage. So it will be the balloon at the HIGHEST temperature that will leak the fastest. This is also true for Helium. Other gases obey the Ideal Gas Law.
What happens to the volume of Balloon left on a sunny windowsill?
It would increase. The balloon would expand because when temperature increases, volume increases as well.
What happens to hydrogen when it is in a balloon?
The hydrogen in a sealed rubber party balloon is compressed slightly by the balloon rubber. So its density decreases a little, its pressure increases, and its temperature increases. But the temperature soon returns to the ambient temperature as heat is lost through the balloon wall. Also, the hydrogen will not stay in the balloon for long because it will leak out through pores in the rubber.
How hot and cold temperature affect air balloon?
When the balloon is hot the density of the air in it decreases and hence the upward thrust on the balloon increases and the balloon moves up and viceversa.
How does temperature affect the size of a balloon?
When the temperature is colder the particles in the balloon travel slower, making the balloon not able to increase in size it decreases.When the temperature is hot it allows the balloon to expand because the particles in the balloon are moving rapidly. in conclusion the the cold makes the balloon decrease in size and the heat allows it to expand.
How does Jacques Charles law relate to aerodynamics?
He 'flew' in helium balloons. Volume increases as temperature increases. In a hot air balloon temp increases so volume increases and some air must leave the balloon. The balloon now has lift because it weighs less than the cold air outside the balloon, just like buoyancy of a boat in water.
How will volume of a balloon change if pressure remains constant but temperature increases?
The volume will increase in proportion to the increase in absolute temperature.
A weather balloon full of helium with a volume of 12.9 L at 22oC is sitting inside an aircraft hangar The temperature of the hangar decreases to 13oC Which equation would be easiest to use to find t?
(v1/t1) = (v2/t2)
Why would cooling the gas in an air balloon make the balloon contract?
== == According to Charles's Law, "At constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases." Therefore, if the temperature of the gas is decreased, the volume of the gas will decrease proportionally, and the balloon will contract.
What woul happen to the volume of the 100L weather balloon if its temperature increases from 25 C TO 125 C while the external pressure remain constant?
The universal gas equation is PV = nRT (Pressure x Volume = Number of moles x Universal Gas Constant x Temperature in Kelvin/Rankin). So - if Pressure is constant, the number of moles is constant, but the temperature increases from 25C (298 K) to 125C (398K) - a 34% increase, a similar 34% increase in volume will occur.
What happens to the speed of the particles inside an air-filled balloon if the temperature of the balloon increases?
They move faster.Particles on the outside of the balloon are slower.The particles will move faster due to an increase in their kinetic energy.
Why do balloons pop in sunlight and not in a shadow?
This is the best answer I can think of... In the sunlight, balloons receive energy from the infa-red radiation from the sun. pV=nRT... ie. for a balloon at roughly the same pressure, volume is proportional to temperature. This means that if temperature increases, volume of the balloon increases and so it pops.
What happens to a balloon kept in a very warm greenhouse?
The balloon will increase in size because the average kinetic energy of the gas molecules in the balloon will increase when the temperature increases .... Therefore the balloon from the greenhouse will increase its size and if we bring the ballonext back to the normal room temperature then the balloon will comega back to its original size ... THANK YOU FOR READING !
