Effective = RMS= average
Not for a sine wave it isn't.
The r.m.s. value of a sine wave is 1.11 x the average, or mean, value.
The "effective" value is not a term which I've seen in any of my reference books.
A; AC. is a sinusoidal wave it has zero potential at some time and speed potential at its peaks. So overall the real effective value to do work is referred by this term. Effective.
The effective value of an AC = AC/√2. Example: the effective value of 8.5 V AC is 6.01 V, because 8.5/√2=6.01 Hope that helped :)
i think average value of current in ac current is zero.
The rms value of a sine wave current is 0.707 Imax. So the answer to your quesion is 0.707 x 4 = 2.83 A.
The average value of the alternating current (AC) in the circuit is calculated by finding the root mean square (RMS) value of the current waveform. This value represents the equivalent direct current that would produce the same amount of power dissipation in a resistor as the AC current.
The maximum value of the current in an AC circuit depends on the frequency of the voltage source. As the frequency increases, the maximum current value also increases.
EFFECTIVE HOW ABOUT AVERAGE .639 of peak.AnswerThe 'effective' value of an a.c. voltage (or current) is the same as its 'root-mean-square' (r.m.s.) voltage which, for a sinusoidal waveform, is 0.707 Umax.The 'average' value of an a.c. voltage (or current) is zero over a complete cycle, or 0.639 Umax, over half a cycle (usually applied to rectified waveforms).
With an AC and a DC voltage source in series, the DC voltage can be added to the RMS value of the AC voltage to give the effective voltage.
In AC supply, the RMS current is the effective current for power used in a resistive circuit. This is defined as the square root of the mean value of the square of the current, taken over a whole cycle. The RMS current dissipates power at the same rate as a DC current of the same value. A light bulb of course gives out light dependent on the current through the filament. So if the RMS current and the DC current are the same value, the light produced will be equal. With AC supply, the RMS value of current and volts is 1/(square root of 2) x the peak value, so peak value = 1.414 x RMS value. If you supplied DC at volts and current equal to the peak AC value, the power given to the light bulb would clearly be greater. Therefore to answer your question you have to specify what relative values your AC and DC supplies have.
The instantaneous value of an alternating current (AC) is the value of the current at a specific moment in time. It is constantly changing direction and magnitude due to its alternating nature, so the instantaneous value represents its value at that precise instant.
AC: Alternating CurrentThe current oscillates cyclically between a maximum and an minimum.DC: Direct CurrentThis is fixed. The current is always at a constant value.
A.C. quantities are always expressed in root-mean-square(r.m.s.) values, unless otherwise stated. For sinsoidal waveform, this equates to 0.707 times the peak value. For example, an AC current with an amplitude of 100 A has an r.m.s. value of 70.7 A.An a.c. current expressed as an r.m.s. value will do exactly the same amount of work as a d.c. current of the same value. In other words, a 50 A (r.m.s.) a.c. current will do exactly the same amount of work as 50 A d.c. This is why r.m.s. values are also referred to as 'effective values' of a.c..