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heat developed = 5*5*20*30 = 15000 joules

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With the information supplied, you can only determine the work done (W) by the circuit, not the heat (Q). To do so, you will need to know the mass (m) and specific heat capacity (C) of the conductor, and the temperature-difference between the conductor and its surroundings. The equation you need to do this is:

W - Q = m C (Tf-Ti)

With the information supplied, you can only calculate the work done: W = I2Rt.

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Q: An electric iron of resistance 20 ohms takes a current of 5A Calculate the heat developed in 30 seconds?
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