This is the chromate anion. It is written CrO42- . It is tetrahedral in shape (like methane). It gives a yellow colour to salts that contain it such as K2CrO4.
Chromate.
Two Chromium Atoms, and 3 Oxygen Atoms. (Cr2O3)
Since oxygen atoms can only accept two electrons, the balance of charges for the overall neutral molecule suggests that the two chromium atoms must each have donated half of the electrons to the oxygen atoms. Therefore, the total number of electrons required for all three oxygen atoms to reach a noble gas configuration is 3 atoms*2 electrons/atom=6 electrons Dividing this up between the two chromium atoms: 6 electrons/2 atoms=3 electrons/atom Therefore, each chromium atom bears a positive charge (since it donated electrons) of 3+.
Cr(VI) should have no unpaired electrons and have no color, but when bound to oxygen, charge transfer occurs from the O 2-. CrO4 (chromate) has four oxygens which all charge transfer to the Chromium giving orange color. In Cr2O7 (dichromate) one oxygen bridges between the two Chromium atoms so each only gets charge transfer from three oxygens. Cr(VI) should have no unpaired electrons and have no color, but when bound to oxygen, charge transfer occurs from the O 2-. CrO4 (chromate) has four oxygens which all charge transfer to the Chromium giving orange color. In Cr2O7 (dichromate) one oxygen bridges between the two Chromium atoms so each only gets charge transfer from three oxygens.
2(2+3)=10 atoms 4 chromium atoms and 6 oxygen atoms
The compound is Chromium(III) Oxide. Chromium is 3+, since the compound has to have a charge equal to 0. Since there is 2 chromium atoms each chromium atom must have a charge of 3+ to balance out the 3(2-) charges of each oxygen atom; 2x+3(-2)=0, transpose for x(chromium), (in case you need the working out).
Two Chromium Atoms, and 3 Oxygen Atoms. (Cr2O3)
Since oxygen atoms can only accept two electrons, the balance of charges for the overall neutral molecule suggests that the two chromium atoms must each have donated half of the electrons to the oxygen atoms. Therefore, the total number of electrons required for all three oxygen atoms to reach a noble gas configuration is 3 atoms*2 electrons/atom=6 electrons Dividing this up between the two chromium atoms: 6 electrons/2 atoms=3 electrons/atom Therefore, each chromium atom bears a positive charge (since it donated electrons) of 3+.
Cr(VI) should have no unpaired electrons and have no color, but when bound to oxygen, charge transfer occurs from the O 2-. CrO4 (chromate) has four oxygens which all charge transfer to the Chromium giving orange color. In Cr2O7 (dichromate) one oxygen bridges between the two Chromium atoms so each only gets charge transfer from three oxygens. Cr(VI) should have no unpaired electrons and have no color, but when bound to oxygen, charge transfer occurs from the O 2-. CrO4 (chromate) has four oxygens which all charge transfer to the Chromium giving orange color. In Cr2O7 (dichromate) one oxygen bridges between the two Chromium atoms so each only gets charge transfer from three oxygens.
2(2+3)=10 atoms 4 chromium atoms and 6 oxygen atoms
The compound is Chromium(III) Oxide. Chromium is 3+, since the compound has to have a charge equal to 0. Since there is 2 chromium atoms each chromium atom must have a charge of 3+ to balance out the 3(2-) charges of each oxygen atom; 2x+3(-2)=0, transpose for x(chromium), (in case you need the working out).
Total 5 atoms in chromate (1 of Chromium and 4 of Oxygen)
Chromate is an anion which contains 4 atoms of oxygen, and 1 of Chromium
The possible oxidation numbers for iron cations are +2 and +3. Oxygen in oxyanions is usually assigned an oxidation number of -2, producing a total negative charge of -14 for the seven oxygen atoms in a dichromate anion. If the iron cation has an oxidation number of +2, the two chromium atoms must have a total oxidation number of +12, which is possible when each chromium atom has an oxidation number of +6. An iron (III) cation would require the chromium atoms to have a non integral charge, which is not possible since electrons with half charges are not known. Therefore, the oxidation number of iron in the compound is +2 and the oxidation number for chromium is +6.
Oxygen -2 Hydrogen +1
ALL atoms whatsoever DO NOT have a charge!! They're neutral.
ALL atoms whatsoever DO NOT have a charge!! They're neutral.
The answer is + 6 The way I figured it out was that O has a -2 charge. -2 times 7 is - 14. to leave -2 you need a +12 charge. So you divide 12 by 2 because you have 2 Cr and you get 6