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An object occupies 3 4 of the loew power of field view which is 2 mm diameter what is the size of the object?
Kseniasatterfield
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If the size of the high-power field is 1.2 mm an object that occupies approximately a third of that field has an estimated diameter of?
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
What happens to the diameter of the field of the view when you change for low to high power?
The diameter of a field is decreased by 1.5 millimeters when changed from low power to high power magnification.
What is the diameter of the high power field of a microscope in micrometers?
the diameter of the high power field microscope is 500 micrometers
How big is the worm relative to the diameter of the field of view?
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power
How would you estimate the size of object viewed under high power objective lens 40 times if you were given the size of the field diameter when using low power objective lens 4 times?
the naswe is 400
Why is an object no longer in view as one switches from low power to high power using the microscope?
At a higher power the field of view is smaller and the object may no longer be in the field of view. Or it may have gone out of focus.
Why is locating an object more difficult if you start with the high-power objective rather than the low power obejctive exspically the brightness whats up with that?
The reason it is more difficult is that the 'field of view' is much smaller, the higher the objective power. In other words, you don't have to be so exactly 'on target' with a lower objective power, as the field of view is larger in proportion to the object being viewed, so the object can be farther off to one side or the other, and still be seen. Once found in the lower power field, center the object in the field and then switch to the higher power- the object should then be in the higher power field of view. This is true for microscopes and telescopes, as well as any instrument that magnifies at different powers of magnification.
Diameter of the field of view in millimeters when using the 4X objective?
five
How do you determine the diameter of the field of view?
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power and further reduced to 0.4 millimeters when you switch to high power. Covert the measurment for the field of view from millimeters to microns, the conventional unit of measurment in microscopy. There are 1000 microns in one millimeter. Low power: 4mm= 4,000um Medium power: 1.7mm= 1,700um High power: 0.4mm= 400um
Why is it important that the object is centered in the field of view before switching to a higher power objective?
WHY IS IT IMPORTANT THAT THE IMAGE IS CENTERED IN THE FIELD OF VIEW BEFORE SWITCHING TO A HIGHER POWER
What does the volume mean?
Depending on context, "volume" can mean a book forming part of a work or series, the amount of space that a substance or object occupies, or quantity or power of sound.
Why does low power have the largest diameter field of vision?
It is focused on the largest area of vision by being the most "zoomed out", so you are looking at a much greater area than the high power field of view.
