It is focused on the largest area of vision by being the most "zoomed out", so you are looking at a much greater area than the high power field of view.
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
The 4x objective lens provides the largest field of view because it has a lower magnification power, allowing you to see a larger area of the specimen at once. The 40x objective lens has a higher magnification power, resulting in a smaller field of view but greater detail.
When you change from low power to oil immersion high power on a microscope, the field of view decreases. This is because high power objectives have a narrower field of view due to higher magnification, leading to a more detailed but smaller area being visible through the lens.
As you move from low power to high power, the depth of field decreases. This means that at high power, the area in focus becomes smaller and more limited compared to low power. This is due to the increased magnification at high power which results in a shallower depth of field.
Medium power objective gives the medium (as oppose to large or small), field of vision and the greatest depth of field. When you move the lens' position (CLose or far from the slide) it would be the middle. Read the textbook it will be of more benefit; or look it up on the internet you are on anyways. Type [edu] with brackets for a page of more scholarly links (if their domain is .edu).
the diameter of the high power field microscope is 500 micrometers
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power
The equation goes like this and works for both medium AND high feild diameter : Medium(High) DIA. = Low Diameter / [Med(High)mag/low mag] Brackets () are NOT for multiplication, they are for the other formula.
You use the 3 objective lenses of a compound microscope to switch powers. There's LOW, MEDIUM, and HIGH power. With LOW power, you can magnify what you're looking at. With HIGH power, you can see things that you can't see with a naked eye.
The diameter of the field of view decreases when changing from low to high power magnification. This is because higher magnification zooms in closer on the specimen, limiting the area of the specimen that can be seen at one time.
To find the diameter of the field of view at high power, you can use the height of the field. If the field is 1.2 mm high and the object occupies one third of that field, then the height of the object is 0.4 mm (1.2 mm / 3). The diameter of the field of view is equal to the height when viewed in a circular field, so it remains 1.2 mm.
If approximately 500 bacteria can fit across your low-power field of vision, and assuming that field is about 1 millimeter wide, each bacterium would be approximately 2 micrometers (μm) in size. This is a typical size for many bacteria, as they generally range from 0.5 to 5 μm in diameter. Thus, the average size of one bacterium in this scenario would be around 2 μm.
When you switch from low to high power on a microscope, the diameter of the field of view decreases because the high-power objective has a higher magnification, which zooms in on a smaller area. This allows for more detailed observation of the specimen at the expense of a smaller field of view.
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power and further reduced to 0.4 millimeters when you switch to high power. Covert the measurment for the field of view from millimeters to microns, the conventional unit of measurment in microscopy. There are 1000 microns in one millimeter. Low power: 4mm= 4,000um Medium power: 1.7mm= 1,700um High power: 0.4mm= 400um
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
To calculate the size of the organism, you would need to know the magnification of the microscope being used. Comparing the field diameter at 400x magnification with the actual size of the organism would give you the scale factor to determine the organism's size. For example, if the field diameter at 400x is 0.5 mm, and the actual size is 50 micrometers, then the organism is 10 times smaller than the field diameter.
Moving the letter e to the center of the low power field helps to ensure that it remains within the field of view when transitioning to high power. This adjustment prevents the specimen from being lost or moving out of sight when switching to a higher magnification.