0
An object weighs 120n on the earth what will be its weight on the moon?
Wiki User
∙ 9y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the weight 75 kg person on the moon?
weight = mass x gravity weight = 75kg x 1.6 weight = 120N
Jill is pulling on John to the right with a force of 120N At the same time Kate is pulling on John to the left with a force of 140 N John who weighs 750 N what is john's acceleration?
Weight is the force on an object due to its mass and location in a gravitational field.As "W = m * g", John's mass can be found.m = W/g = 750 / 10 = 75 kgTo find John's acceleration, it is necessary to find the resultant (net) force on him, as "a = F/m" (Newton's second law).When all the vector forces (from Jill and Kate) are added together, the resultant force comes out to be 20N to the left. (120N right + 140N left = 20N left). Presuming that the weight of John is balanced by a force from the ground, this value can be used to find acceleration.a = F / ma = 20N left / 75kga = 0.2667 ms-2 to the left
What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 ms2?
answer is (D) 120N
Do maps have anything to do with math?
Are you serious? OF COURSE! calculations, calculations, calculations! NORTH SOUTH EAST WEST! 120N, 30S
If a net force of 120N gives an object an acceleration of 1.5 m s s what is the mass of the object?
Force is equal to the acceleration times mass. So, 120 N = 1.5 ((m/s)/s) times mass. So, the mass is 80 kg.
How do you solve convert to inches 10n feet?
1 foot = 12 inches so 10n feet = 10n*12 = 120n inches.
What are 6 even consecutive numbers whose summation is 150?
20, 22, 24, 26, 28, 30ProcedureAssume the numbers are:2n, 2n+2, 2n+4, 2n+6, 2n+8, 2n+10 ........................... (1)Summation = 12n + 30 = 15012n = 120n = 10Subsititute with n = 10 in (1) we get the answer above
What is the number of sides of a regular polygon if the measure of each interior angle is 120 degrees?
(180n - 360)/n = interior angle of any regular n-sided polygon. In this case (180n - 360)/n = 120 ie 120n = 180n - 360 ie 60n = 360 so n = 6 and your figure is a hexagon.
A crate is pushed east across a frictionless surface with a force of 240N and pulled to the east by a rope with a force of 120N What is the net force on the crate?
There is no force of friction, so you would simply add both Net forces together. 240+120 = 360N
150 workers can do a work in n day from second day 4 workers started leaving on each day so work completes in 8 more days find no of days to complete it?
150 workers-- n days-- 'x' amount of work is done by 150 workers in 'n' days 1 worker-- 1 day-- 'x/(150n)' amount of work done by 1 worker in 1 day Let's calculate the amount of work done by the reducing number of workers in n+8 days: Work on first day= Number of workers on first day * amount of work done by 1 worker in 1 day. = 150 * [x/(150n)] Work on second day= Number of workers on second day * amount of work done by 1 worker in 1 day. = 146 * [x/(150n)] Work on (n+8)th day= Number of workers on (n+8)th day * amount of work done by 1 worker in 1 day. = [150+(n+8-1)(-4)] * [x/(150n)] --using arithmetic sequence formula = [122-4n] * [x/(150n)] Total work=[(n+8)/2 * (150 + 122-4n )] * [x/(150n)] --using sum of arithmetic sequence formula = [120n-2n2+1088] * [x/(150n)] x amount of work can be done in n days [120n-2n2+1088] * [x/(150n)] amount of work is done in n+8 days x/n= [ (120n-2n2+1088 )* x/(150n) ] / (n+8) Solving this, we get: n2+15n+56=0 n= -8, -7 Since the days are obtained in negative, I assume there is something wrong with the data in the question.
How do you find the interior angle of a regular polygon given the measure?
The sum of the interior angles of a regular polygon with n sides is 180(n-2). Once you have that number, divide it by n and you have the measure of the individual angles. If you have the measure of one of the angles, call that number M, then we can solve 180(n-2)/n=M ( just working backward) Or 180(n-2)=Mn or 180n-360-Mn=0 For example, say M=90 degrees, which we know will be a rectangle ( quadrilateral). Than we have 180n-360-90n=0 or 90n=360 and n=4 Or maybe M=60 Then 180n-360-60n=0 and 120n=360 so n=3 and it is a triangle as expected.
What force is required to accelerate a body with a mass of 15 kilograms at an 8 meters per secound?
Since you don't tell us anything about friction or any other forces in the body's environment, we have to assume that there aren't any, and answer the question for that case. Any force, no matter how small, will accelerate any body, no matter how big. The greater the force is, the greater the acceleration will be. To find out exactly what the acceleration is, simply divide the force by the mass.
