No. Hydrocarbons are not miscible in water.
19,5 g butane are needed.
Co2(g) + h2o(g)Explanation apex
C4H10
Butane-C4H10 C4H10 - H C4H9 - ? C4H9 + CHO C4H9CHO
It is hard to pinpoint how many carbon atoms are in 2.5g of butane. Roughly, the answer is 1.04 x 10^23 moles. This had to be indicated by figuring out the moles per grams first.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
19,5 g butane are needed.
2c4h10o + 13o2 -----> 8co2 + 10h2o
Co2(g) + h2o(g)Explanation apex
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
Partial answer:CxHy is used to indicate a generic hydrocarbon fuel.A specific hydrocarbon would be, for example, C4H10. That is the molecular formula for Butane.
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O
2 C4H10 (g) + 13 O2 (g) -----> 8 CO2 (g) + 10 H2O (g)
C4H10
C4H10(g) is about -126 kJ/mol C4H10(l) is about -147 kJ/mol
1 mole C4H10 = 58.1222g = 6.022 x 1023 molecules 11.7g C4H10 x 6.022 x 1023 molecules/58.1222g = 1.21 x 1023 molecules C4H10
The chemical formula for butanal is CH3CH2CH2CHO.