Yes.
When a satelite's rotational period is the same as its orbital period, like our moon, the satelite is tidally locked to the body being orbited. Such a rotation rate is known as a synchronous rotation. The effect is that the same side of the satelite always faces the orbited body.
The moon takes approximately 27.3 days to complete one rotation on its axis. This period is known as its sidereal rotation period and is the same as its orbital period around the Earth.
They are the same
It is believed by some that mass of an orbiting body has no effect on its orbital period, a logical conclusion which must follow from the fact that two objects of different weight fall towards the ground at the same speed for example. However, it must be understood that this is possible only because the two falling objects have masses that are negligible compared to the planet that they are falling towards. This scenario no longer applies when we are talking about a body with a significant mass relative to the mass of the body it orbits. Newton's formula for orbital period takes into account the masses of both the orbiting object and the central object being orbited:p2 = 4pi2a3/ G(M1 + M2)Where M1 is the mass of the orbiting body, M2 is the mass of the body being orbited, "a" is the distance between the two, of course G is the Gravitational Constant. When M1 is negligible compared to M2 (such as the mass of a radio satellite compared to the mass of the Earth), M1 can be practically ignored. However, if M1 is significant compared to M2, it cannot. Let us consider what the orbital period would be for several planets, if they could somehow be made to orbit the sun at the same distance as the Earth from the sun. A planet the size of Mars (about a 10th the size of earth) would have an orbital period of one year minus 40 seconds (a negligible difference from Earth's period to be sure). A planet the size of Jupiter (about 300 times the size of earth) would have an orbital period of about 1 year and 4 hours. If you can imagine a giant planet with a mass 4 times that of Jupiter, it would have an orbital period of about 1 year and 17 hours.
Since all other things are equal, it will take a year to go around the star. The mass of the planet hardly has any effect on its orbit - unless this mass is significant, compared to the star.
Same as it's orbital period, about 27.32 days.
Mercury
Triton's revolution period is the same as its orbital period, or approximately 5.877 days.
A geosynchronous satellite is a satellite in geosynchronous orbit, with an orbital period the same as the Earth's rotation period.
The moon's orbital period is the same as its rotational period, so the same side of the moon always faces the earth.
Yes, the base and the length are the same thing.
No
No.
yes they are the same things
It's about 88 Earth Days.
It is not, because the altitude of the orbit is related to the period. If two satellites have the same orbital period, then they have the same altitude.
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.