Sodium is a metal. Fluorine is a gas. Both elements are highly reactive and will produce (in a nearly explosive reaction) a compound called sodium fluoride which is an ionically bonded salt.
When fluorine and sodium react together, they form an ionic compound called sodium fluoride. In this compound, sodium donates an electron to fluorine, creating positively charged sodium ions and negatively charged fluoride ions, making it an ionic compound.
The ionic compound for fluorine and sodium is sodium fluoride, which has the chemical formula NaF. Sodium donates its electron to fluorine to form a positively charged sodium cation and a negatively charged fluoride anion, which are held together by ionic bonds.
The electron configuration for sodium is [Ne] 3s1 and for fluorine is [He] 2s2 2p5. When sodium donates its outer electron to fluorine, sodium becomes Na+ and fluorine becomes F-. The ionic compound formed is sodium fluoride (NaF).
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
The compound formed when sodium reacts with fluorine is sodium fluoride, with the chemical formula NaF. Sodium donates one electron to fluorine to form an ionic bond between the two elements.
Yes and this compound is sodium fluoride: NaF.
Sodium and fluorine will form an ionic compound named sodium fluoride with the formula NaF.
When fluorine and sodium react together, they form an ionic compound called sodium fluoride. In this compound, sodium donates an electron to fluorine, creating positively charged sodium ions and negatively charged fluoride ions, making it an ionic compound.
The ionic compound for fluorine and sodium is sodium fluoride, which has the chemical formula NaF. Sodium donates its electron to fluorine to form a positively charged sodium cation and a negatively charged fluoride anion, which are held together by ionic bonds.
The electron configuration for sodium is [Ne] 3s1 and for fluorine is [He] 2s2 2p5. When sodium donates its outer electron to fluorine, sodium becomes Na+ and fluorine becomes F-. The ionic compound formed is sodium fluoride (NaF).
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
Sodium fluoride.
Sodium (Na) is the element that would most likely form an ionic compound with fluorine (F). Sodium readily gives up an electron to fluorine to achieve a stable electron configuration, forming sodium fluoride (NaF) which is an ionic compound.
When sodium and fluorine combine, they form sodium fluoride (NaF). This compound is an ionic compound where sodium loses an electron to fluorine, resulting in the formation of a stable ionic bond. Sodium fluoride is commonly used in dental products like toothpaste for its ability to prevent tooth decay.
The compound formed when sodium reacts with fluorine is sodium fluoride, with the chemical formula NaF. Sodium donates one electron to fluorine to form an ionic bond between the two elements.
The ionic compound formed when sodium (Na) and fluorine (F) react is sodium fluoride, with the chemical formula NaF. In this compound, sodium (Na) donates an electron to fluorine (F) to form an ionic bond between the positively charged Na+ ion and the negatively charged F- ion.
If fluorine combines with an element such that their electronegativity difference is more than 1.7, then they will form an ionic compound. Example:- Hydrogen fluoride is an ionic compound. Hydrogen has electronegativity of 2.1 and fluorine has 4.0. So, the difference is 1.9. Therefore, it is an ionic compound.