A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
NaF = Sodium Fluoride
ionic- Barium is a metal, and Fluorine a non-metal.
Na(+) and F(-) form NaF sodium fluoride, an ionic bond.
An electron is transferred from sodium to fluorine. to form Na+ and F-
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
NaF = Sodium Fluoride
Ionic. The usual rule is that when you have a metal (sodium) and combine it with a nonmetal (fluorine), there is an ionic bond formed.
Sodium and fluorine will form an ionic compound named sodium fluoride with the formula NaF.
Yes and this compound is sodium fluoride: NaF.
Sodium fluoride.
ionic- Barium is a metal, and Fluorine a non-metal.
Na(+) and F(-) form NaF sodium fluoride, an ionic bond.
An electron is transferred from sodium to fluorine. to form Na+ and F-
Sodium Fluoride is an Ionic Compound. It's Fluorine and Sodium with the formula NaF.
NaF is the empirical formula
Because sodium is a metal and chlorine is a non metal, it is ionically bonded.