A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
Yes, sodium and fluorine form an ionic bond to create sodium fluoride. Sodium has one electron to lose, while fluorine has one electron to gain, leading to the transfer of electron from sodium to fluorine resulting in the formation of an ionic bond.
The ionic compound for fluorine and sodium is sodium fluoride, which has the chemical formula NaF. Sodium donates its electron to fluorine to form a positively charged sodium cation and a negatively charged fluoride anion, which are held together by ionic bonds.
The cation,Na +and the anion,F -form the ionic compound,NaF============sodium fluoride.
Yes, fluorine and sodium will form an ionic bond. Fluorine is a highly electronegative element that will attract electrons from sodium, a highly electropositive element, resulting in the transfer of electrons and the formation of an ionic bond between them.
A bond between fluorine and sodium would be covalent (non-ionic), as they are both nonmetals, and the difference in their electronegativities is less than 1.7.
Ionic bond is used in NaF. Sodium (Na) is a metal and fluorine (F) is a non-metal, so they form an ionic bond where electrons are transferred from sodium to fluorine.
Yes, sodium and fluorine form an ionic bond to create sodium fluoride. Sodium has one electron to lose, while fluorine has one electron to gain, leading to the transfer of electron from sodium to fluorine resulting in the formation of an ionic bond.
The ionic compound for fluorine and sodium is sodium fluoride, which has the chemical formula NaF. Sodium donates its electron to fluorine to form a positively charged sodium cation and a negatively charged fluoride anion, which are held together by ionic bonds.
Sodium (Na) is the element that would most likely form an ionic compound with fluorine (F). Sodium readily gives up an electron to fluorine to achieve a stable electron configuration, forming sodium fluoride (NaF) which is an ionic compound.
The cation,Na +and the anion,F -form the ionic compound,NaF============sodium fluoride.
Yes, fluorine and sodium will form an ionic bond. Fluorine is a highly electronegative element that will attract electrons from sodium, a highly electropositive element, resulting in the transfer of electrons and the formation of an ionic bond between them.
NaF is an ionic compound. It is composed of a metal cation (sodium, Na+) and a non-metal anion (fluoride, F-), which form a strong ionic bond due to the transfer of electrons from sodium to fluorine.
The electron configuration for sodium is [Ne] 3s1 and for fluorine is [He] 2s2 2p5. When sodium donates its outer electron to fluorine, sodium becomes Na+ and fluorine becomes F-. The ionic compound formed is sodium fluoride (NaF).
Sodium and fluorine will form an ionic compound named sodium fluoride with the formula NaF.
Sodium is a likely candidate to form an ionic compound with fluorine because sodium is a metal with 1 valence electron, while fluorine is a non-metal with 7 valence electrons. When sodium loses its electron and fluorine gains it, an ionic bond is formed between the two elements.
Sodium is a metal. Fluorine is a gas. Both elements are highly reactive and will produce (in a nearly explosive reaction) a compound called sodium fluoride which is an ionically bonded salt.