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Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
It depends on the material. In metals, the resistance increases with temperature.
as the temperature rises,the drift velocity increases hence relaxation time decreases and resistance increases.
For conductor the resistance (R) is directly proportional to the length (L) of the conductor, and the area of cross-section (A). When you stretch the conductor to increase its length, its area of cross-section will decrease. The decrease in area of cross-section can be found in the following way: The volume of the cylinder will remain same. The initial volume of the cylinder is = A Х L Suppose, the area of cross-section becomes A/ and the resistance becomes R/. Hence, the resistance increases 4 times. Hope this helps you, Keep posting and have a nice day!
It means that the "Resistance of the Conductor varies directly with the temperature between a range or up to a limit". Varies Directly Means : If one increases the other too increases and vice versa.
increases
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
Specific resistivity is directly proportional to area of cross section of the conductor and specific conductivity is the inverse of specific resistivity. So we can say , Specific conductivity is directly proportional to area of cross section of the conductor.
By deviding the multification of line pressure and screw dia with the crosssectional area of hydralic cylinder piston.
I assume you meant pressure to voltage. The resistance of a conductor is directly proportional to the temperature of the conductor. If the temperature of the conductor increases due to increased current, then the resistance tend to increase too.
Conductor resistance = Conductor resistivity * Length of conductor / Cross sectional area of conductor. So. It is directly proportional to material & conductor length. And inversely proportional to the cross sectional area of conductor.
Resistance is inversely-proportional to the cross-sectional area of a conductor. When a d.c. current flows, the charge carriers distribute themselves across the whole of the conductor's cross-section. When a.c. current flows, due to something called the 'skin effect', the charge carriers tend to flow towards the surface of the conductor -thus reducing the effective cross-sectional area of the conductor. So, the resistance to a.c. is higher than the resistance to d.c. At mains' frequencies (50/60 Hz), the 'skin effect' is relatively low, but the effect increases significantly with an increase in frequency. So the difference between 'd.c. resistance' and 'a.c. resistance' increases as the frequency increases.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
It depends on the material. In metals, the resistance increases with temperature.
as the temperature rises,the drift velocity increases hence relaxation time decreases and resistance increases.
This depends on the type of conductor. If the conductor has a positive coefficient the resistance will increase. If the conductor has a negative temperature coefficient the resistance will decrease.