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A pH of 4.29 corresponds to a hydrogen ion concentration of 10-4.29, which equals 10-5 X 10+0.71, since

0.71 - 5 = -4.29. 10+0.71 = 5.1, to the justified number of significant digits. By definition, Ka = [H+]X[CN-]/[HCN], and in the absence of other sources of cyanide anions, [H+] = [CN-]. Within the number of significant digits given, [HCN] = 0.16, and Ka then = (5.1 X 10-5)2/0.16 = 1.6 X 10-8.

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Q: At a certain temperature a 0.16 m solution of hcn has a pH of 4.29 what is the ka of hcn at this temperature?
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