Above 2000 degree centrgate.
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
2 h2 + o2---------2 h2o
= H2+O2 =2H2+O2=2H2O
H2 and O2.
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
This simple equation is: 2H2 + O2 = 2H2O
It is not balanced. There should be a 2 in front of H2 and H2O
H2 +o2 --->h2o
H2 +o2 --->h2o
the product of an equation is the multiples made by them