Water (H2O) is made of 2 molecules of hydrogen and one oxygen. When you separate water into a gaseous state by electrolysing the water, you have separated the oxygen and hydrogen molecules. If you were to bubble that gas (Brown's gas) through water, the water absorbs the extra 2 molecules of hydrogen and one molecule of oxygen. 2H2O + 2H2 + O2 = 2[H3O]+ + 2[OH]-
H2 + 2OH ---> 2 H2O is the balanced equation
2h2 +o2 -------> 2h2o
H2o2=2h2o+o2
Balanced equation: 2 H2 + O2 --> 2 H2O
The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
The reactants of H2O are, of course, Hydrogen and Oxygen, but the chemical equation is not as simple to understand.The chemical equation of water is: H4+O2 ---> 2H2OIt is complicated to understand, but the O has to be changed to O2 in the reactants side due to the H2, which was changed to H4 in order to balance out the equation.
This equation is 2 H2O (liquid) = 2 H2 (gas) + O2 (gas)There must be 4 atoms / 2 diatomic molecules of hydrogen on each side to yield O2This is the electrolysis of water.
= H2+O2 =2H2+O2=2H2O
This simple equation is: 2H2 + O2 = 2H2O
2SO2 + O2 + 2H2O -------> 2H2SO4
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
H2 and O2.
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
2h2 + o2 -> 2h2o stupid wiki is not allowing capitalization again!! Know that all the letters are capitals.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
C2H6O + O2 = C2H4O2 + H2O is balanced but not sure if this is what would happen