The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
H2o2=2h2o+o2
catalase
HSO2 + H2O2+H2O----------HSO4 + O2 +2H+High pH will prevent reacction
hydrogen peroxide (2H202)
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
H2o2=2h2o+o2
The reaction is:2 H2O2-----------------2 H2O + O2
The reaction is:2 H2O2-----------------2 H2O + O2
The simplified chemical reaction is:H2 + O2 = H2O2
The equation as given can not be balanced, because it is incomplete: When hydrogen peroxide decomposes to produce water, it also produces oxygen. A proper, balanced equation for the reaction is 2 H2O2 -> 2 H2O + O2.
If you had the equation of H2O2(aq) ==> H2O(l) + O2(g), it wouldn't be balanced, so is incorrect. If it were 2H2O2 ==> 2H2O + O2, then it would be balanced, and H2O2 would be an example of a disproportionation reaction, where H2O2 is both the oxidizing and reducing agent, i.e., the O is both oxidized and reduced to form H2O and O2. Not sure if this is what you are looking for as the question is rather vague.
catalase
When Hydrogen Peroxide (H2O2) is heated, it produces water (H2O) and Oxygen (O2). The chemical reaction is: 2 H2O2 + heat ---> 2 H2O + O2
I'm no chemist, but I do know that you need to balance the sides in this and add another oxygen molecule to the products. the result would be S+H2O2 or SO+H2O (I think).
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
2H2O2 in the prescence of catalase results in 2 H2O + O2