hydrogen peroxide (2H202)
The balanced reaction for N2H4 + H2O2 --> N2 + H2O is N2H4 + 2H2O2 --> N2 + 4H2O
HSO2 + H2O2+H2O----------HSO4 + O2 +2H+High pH will prevent reacction
synthesis reaction
When the equation kmno4 plus mgs k2s plus mgmno42 is balanced, the correct set of coefficients is 2111.
It is balanced.
h2o2
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
If you had the equation of H2O2(aq) ==> H2O(l) + O2(g), it wouldn't be balanced, so is incorrect. If it were 2H2O2 ==> 2H2O + O2, then it would be balanced, and H2O2 would be an example of a disproportionation reaction, where H2O2 is both the oxidizing and reducing agent, i.e., the O is both oxidized and reduced to form H2O and O2. Not sure if this is what you are looking for as the question is rather vague.
It is very clear: the compounds resulted from this reaction are water and oxygen.
2H2O2 in the prescence of catalase results in 2 H2O + O2
Substrate.
Well, if that those symbols represent molecules, where H2O2 is hydrogen peroxide and H2O is water, then the it makes no sense, "hydrogen peroxide plus water plus zero". If on the other hand, those are just regular variables, then there's really nothing wrong with it, other than the facts that it can be simplified, and that there is no equality given (ie. it's not an equation, just a set of terms).
The balanced reaction for N2H4 + H2O2 --> N2 + H2O is N2H4 + 2H2O2 --> N2 + 4H2O
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
No. There are two O's on the right side and three on the left. The balanced form is 2 H202 -> 2 H20 + 02. All of the O's are the letter 0 in this equation. All numbers are subscripts except the two 2's in front of the H's that have a space after them. I've taken college-level chemistry, so I remember how to do this.
HSO2 + H2O2+H2O----------HSO4 + O2 +2H+High pH will prevent reacction