It is very clear: the compounds resulted from this reaction are water and oxygen.
H2o2
H2O2 + 2 KI --> 2 KOH + I2
The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
The chemical symbol for hydrogen peroxide is H2O2
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
I think what you are thinking of is the decomposition of Hydrogen peroxide, which has the equation: 2H2O2 --> O2 + 2H2O which when balanced then equals 8. 2(H2O2) --> 2H2O +O2 |4*2|=8 -->|3*2|=6 +2= 8 That is the entire equation completed and balanced. Hope it helped!
Not enough information
2 H2O2 ---> 2 H2O + O2 + energy, it's exothermic
H2O2 is the chemical formula. Since hydrogen peroxide is not an element it does not have a symbol.
H2O2 is a clear liquid known as hydrogen peroxide. It is a compound with an oxygen-oxygen single bond. Concentrated H2O2 is often used as a propellant in rocketry.
If you had the equation of H2O2(aq) ==> H2O(l) + O2(g), it wouldn't be balanced, so is incorrect. If it were 2H2O2 ==> 2H2O + O2, then it would be balanced, and H2O2 would be an example of a disproportionation reaction, where H2O2 is both the oxidizing and reducing agent, i.e., the O is both oxidized and reduced to form H2O and O2. Not sure if this is what you are looking for as the question is rather vague.
The equation as given can not be balanced, because it is incomplete: When hydrogen peroxide decomposes to produce water, it also produces oxygen. A proper, balanced equation for the reaction is 2 H2O2 -> 2 H2O + O2.