H2O2 + 2 KI --> 2 KOH + I2
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
When chlorine gas is added to potassium iodide solution, potassium chloride and iodine are formed. The balanced chemical equation for this reaction is 2KI + Cl2 → 2KCl + I2.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
A precipitate of Lead iodide and Potassium nitrate are formed
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
potassium