FeOH3CL
Fe(OH)2 + 2 HCl => FeCl2 + 2 H2O
Fe(NO3)3 + 3HCl = FeCl3 + 3HNO3
all are aqueous forms
FES + 2 HCl ---> FECl2 + H2S is the balanced equation.
Fe + 2HCl --> FeCl2 + H2
Zn(NO3)2 + FeSO4 -> ZnSO4 + Fe(NO3)2
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
I will assume iron II. Fe + 2HCl -> FeCl2 + H2
the equation would look like: 2(NO3) + Fe --> Fe(NO3)2 the 2 in front of the NO3 is there to balance the equation.
Zn(NO3)2 + FeSO4 -> ZnSO4 + Fe(NO3)2
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
Yes, it will because iron is more reactive than lead. Unbalanced Equation : Fe + Pb(NO3)2 => Pb + Fe(NO3)3 Balanced Equation : 2Fe + 3Pb(NO3)2 => 3Pb + 2Fe(NO3)3
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
I will assume iron II. Fe + 2HCl -> FeCl2 + H2
the equation would look like: 2(NO3) + Fe --> Fe(NO3)2 the 2 in front of the NO3 is there to balance the equation.
FeCl3 + 6KSCN --> [Fe(SCN)6]-3 + 6K+ + 3Cl- This is a complex ion equation. K has a charge of +1 and Cl has a charge of -1 but since these form an aqueous solution, they are seperated. Put together, the equation cannot be balanced.
Fe(NO3)3
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
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Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================
Fe(NO3)3+3NaOH--->Fe(OH)3+3NaNO3