FeCl3 + 6KSCN --> [Fe(SCN)6]-3 + 6K+ + 3Cl-
This is a complex ion equation. K has a charge of +1 and Cl has a charge of -1 but since these form an aqueous solution, they are seperated. Put together, the equation cannot be balanced.
The balanced equation for the reaction of iron with chlorine is: Fe + Cl2 -> FeCl3.
This equation is 2 Fe + 3 Cl2 -> 2 FeCl3.
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
Ferric Chloride = FeCl3Ammonium Hydroxide = NH4OHFerric (III) Chloride + Ammonium Hydroxide = Ferric (III) Hydroxide + Ammonium Chloride FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl
2Fe + 3Cl2 ---> 2FeCl3 (iron(III) chloride) Fe +Cl2 -> FeCl2 (iron(II) chloride)
When you mix FeCl3 and KSCN, a blood red color forms due to the formation of Fe(SCN)2 complex. When AgNO3 is added to this solution, a white precipitate of AgSCN is formed, indicating the presence of thiocyanate ions in the solution.
The balanced equation for ferric chloride (FeCl3) reacting with sodium hydroxide (NaOH) is: FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
The balanced molecular equation for FeCl3 + CoCl2 is: 2FeCl3 + 3CoCl2 → 2FeCl2 + 3CoCl3
The balanced equation for the reaction of iron with chlorine is: Fe + Cl2 -> FeCl3.
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
This equation is 2 Fe + 3 Cl2 -> 2 FeCl3.
1. Add a small quantity of the FeCl3 solution into the Na2S(aq.). 2FeCl3+3Na2S=2FeS↓+6NaCl+S↓ the following is the ionic reaction equation 2Fe3+ + S2- = 2FeS↓+ S↓ 2. Add a small quantity of the Na2S solution into the FeCl3(aq.) 2FeCl3 + Na2S =2FeCl2 + 2NaCl + S↓ the following is the ionic reaction equation 2Fe3+ + S2- = S↓ + 2Fe2+
the equation Fe + Cl2 = FeCl3 would be balanced as...2Fe + 3Cl2 = 2FeCl3
The formula for iron(III) chloride is FeCl3. Equations are only for chemical reactions and they show what reactant(s) form what product(s).
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
Ferric Chloride = FeCl3Ammonium Hydroxide = NH4OHFerric (III) Chloride + Ammonium Hydroxide = Ferric (III) Hydroxide + Ammonium Chloride FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl
FeCl3 + H2O4-2 +Zn