Since H6 = +1 x6 = +6 and O= -2 . You are left with +4, therefore each C atom has -2
In CH3COOH, the carbon atom has an oxidation number of +3. This is because the hydrogen atoms have an oxidation number of +1 each, the oxygen atom has an oxidation number of -2, and overall the molecule is neutral.
-3 on the first C and +3 on the second C
C= -2
h= +1
o= -2
2-
In CH3COOH (acetic acid), the oxidation number of carbon is +3, oxygen is -2, and hydrogen is +1. The total oxidation number for the molecule is 0 since it is a neutral molecule.
The oxidation number of carbon (C) in acetic acid (CH3COOH) is +3. This is calculated based on the known oxidation numbers of hydrogen (+1) and oxygen (-2) combined with the overall charge of the molecule being neutral.
The oxidation number of acetic acid (CH3COOH) is +3 for carbon in the carboxyl group (COOH), -3 for oxygen, and +1 for hydrogen.
The oxidation number of carbon (C) in CH3COOH is +3. This is because each hydrogen (H) has an oxidation number of +1, and each oxygen (O) has an oxidation number of -2. With this information, we can set up an equation to solve for the oxidation number of carbon: x + 3(+1) + 2(-2) = 0. Solving for x gives us +3 for the oxidation number of carbon.
In CH3OH, the oxidation number of carbon (C) is -2. In HCOOH, the oxidation number of carbon (C) is +2.
In CH3COOH (acetic acid), the oxidation number of carbon is +3, oxygen is -2, and hydrogen is +1. The total oxidation number for the molecule is 0 since it is a neutral molecule.
The oxidation number of carbon (C) in acetic acid (CH3COOH) is +3. This is calculated based on the known oxidation numbers of hydrogen (+1) and oxygen (-2) combined with the overall charge of the molecule being neutral.
The oxidation number of acetic acid (CH3COOH) is +3 for carbon in the carboxyl group (COOH), -3 for oxygen, and +1 for hydrogen.
There are two C atoms. One show s-3 and other shows +3.
The oxidation number of carbon (C) in CH3COOH is +3. This is because each hydrogen (H) has an oxidation number of +1, and each oxygen (O) has an oxidation number of -2. With this information, we can set up an equation to solve for the oxidation number of carbon: x + 3(+1) + 2(-2) = 0. Solving for x gives us +3 for the oxidation number of carbon.
The oxidation number of carbon (C) in CH2O is +2. This is because hydrogen (H) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, so the sum of the oxidation numbers in CH2O must be zero to balance the charge.
The oxidation number of C in CāOā is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
The oxidation number of C in CO3^2- is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of the carbonate ion is 2-, the carbon atom must have an oxidation number of +4 to balance the charge.
The oxidation number for carbon (C) in carbon dioxide (CO2) is +4. Each oxygen atom has an oxidation number of -2, so in the compound CO2, the total oxidation number must equal 0.
The oxidation number is + for C and -2 for O.
The oxidation number of carbon (C) depends on the compound it is in. In most organic compounds, carbon has an oxidation number of +4, +2, 0, or -4.
The oxidation number of C in 3CO is +2, as in carbon monoxide each oxygen has an oxidation number of -2. In 3CO2, the oxidation number of C is +4.